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2 years ago

Help with practice problem

Mathematics

1 answer:

Misha Larkins [42]2 years ago

7 0

Answer:

i think the answer is r=0.5 or r=−3/2−x^2

Step-by-step explanation:

-4r^2-4r=6

step 1. -4r(-4r)= 16r

16r-4r=6

step 2. 16r-4r=12r

12r=6

step 3. /12 on both sides

r= 0.5

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Step-by-step explanation:

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OLga [1]

Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
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The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
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The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
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Answer:

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Step-by-step explanation:

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∵ The average marks of the first 10 students are 17

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∴ Average = 17

∴ N = 10

∵ Average = $\frac{S}{N}$

- Substitute average by 17 and N by 10

∴ 17 = $\frac{S}{10}$

- Multiply both sides by 10

∴ 170 = S

∴ The sum of the marks of the first 10 students is 170

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