The volume of a cube is V=s^3, so s=V^(1/3).
The area of a cube is A=6s^2, using s found above we have:
A=6(V^(2/3))
Let V and S be the volume and area of the larger and v and s be the volume and area of the smaller cube.
A:a
6(V^(2/3)):6(v^(2/3))
V^(2/3):v^(2/3), we are given that V=216 and v=64 so
216^(2/3):64^(2/3)
36:16
9:4
The area of this polygon is 35.5 units∧2.
Good luck!!!!
first you have to look to the right of that number .check if it is more than 5. if it is ,than add one to the first digit in the quotient. all the other numbers will turn to zeroes.
Answer:
-19/132
Step-by-step explanation:
To add fractions, find the lowest common multiple of the two denominators and multiply accordingly to make both denominators the same. In this case, the lowest common multiple of 11 and 12 is 132, so we need to multiply the first number by 12 and the second by 11. So we get 
= 
=
Answer:
84 cm²
Step-by-step explanation:
Surface area of the polyhedron = the sum of the areas of each parts of the net = area of 2 triangles + area of each of the 3 rectangles
Area of 2 triangles:
Base = 4 cm
Height = 3 cm
Area of the 2 triangles = 2(½*base*height)
= 2(½*4*3) = 4*3 = 12 cm²
Area of rectangle with the following dimensions:
Length = 6 cm
Width = 4 cm
Area = length * width = 24 cm²
Area of rectangle with the following dimensions:
Length = 6 cm
Width = 5 cm
Area = length * width = 30 cm²
Area of rectangle with the following dimensions:
Length = 6 cm
Width = 3 cm
Area = length * width = 18 cm²
Surface area of the polyhedron = 12 + 24 + 30 + 18 = 84 cm²
