All categories

3 years ago

Solve x ym = y x3 for m.

Mathematics

1 answer:

Sholpan [36]3 years ago

5 0

Xym=yx^3
xym/xy=yx^3/yx
m=x^2

You might be interested in

Need help please thank you

Free_Kalibri [48]

Answer:

Step-by-step explanation:

All of them. (6)

4 0

3 years ago

Suppose it takes you 14 hour to drive to the movie theater at a rate of 40 mph. Your friend lives closer to the movie theater th

dezoksy [38]

Answer: (d)

Step-by-step explanation:

Given

It takes 14 hours with 40 mph to reach the theatre

so, the distance traveled is given by

$\Rightarrow d_1=40\times 14\\\Rightarrow d_1=560\ \text{miles}$

It is given that d is the distance from theatre to friend's house

So, d must be less than $d_1$ i.e.

$d$

So, the most appropriate option out of the given is option (d) as d must be less than 560 and it is possible that it maybe less than 160.

7 0

3 years ago

2. The average human heart beats 60 beats per minute. How many times does a heart

love history [14]

Answer:

31536000

Step-by-step explanation:

if the average heart beats 60 beats per minute and there are 525600 minutes in a year multiply

4 0

3 years ago

Read 2 more answers

Does anyone know the answer?

Alex787 [66]

Answer:

£0.60

Step-by-step explanation:

If each pack costs £1.59 and Nadia orders 15 packs,

then the total order before discount = 1.59 x 15 = £23.85

From the table given, we can see that for an order of £23.85 a 2.5% discount will be applied.

Divide £23.85 by 100 to get 1%: £23.85 ÷ 100 = £0.2385

Now multiply by 2.5 to get 2.5%: £0.2385 × 2.5 = £0.59625 = £0.60

Alternatively, the calculation in one expression is:

(1.59 × 15) × 0.025 = 0.59625

7 0

2 years ago

You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5

Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : $E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}$

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = $\dfrac{1.645\times11.5}{\sqrt{20}}$

$\approx4.23$

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0

3 years ago