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VikaD [51]
3 years ago
13

Which of the following figures are quadrilaterals?

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0
Square , rectangle , rombus , parallelogram
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The function y= 19,800/x is a rational function. Use this function to answer each question. What are the asymptotes of the funct
Ilya [14]

Answer:

Step-by-step explanation:

Given the function y = 19800/x

Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

x = 0, y = 0

5 0
3 years ago
Read 2 more answers
Evaluate if a= 28 and b= -3 a/4+b
patriot [66]

Answer:

4

Step-by-step explanation:

divide the numbers


subtract the numbers


final answer:
= 4

8 0
1 year ago
Solve the equation 6x+3y=15for y what does y equal if x=2 if x=5
avanturin [10]
6x+3y=15
6*2+3y=15
12+3y=15
      3y=3
        y=1

6x+3y=15
6*5+3y=15
30+3y=15
      3y=-15
        y=-5

The answers is y=1 & -5

3 0
3 years ago
F(x) = cot x PRE CALC HELP PLS?!
alisha [4.7K]
Check the picture below.

is it even?  well, even functions use the y-axis as a mirror, so a pre-image on the right-side, will be a mirror of the image on the left-side, but in this case it isn't so, if you put a mirror right on the y-axis, the left-side will look a bit different.

does it have a zero at x = 0?  well, just look at the graph, is the line touching the x-axis at 0? nope.

does it have an asymptote at 0?  well, surely you can see it right there.

8 0
3 years ago
A ball is thrown straight up from the top of a building that is 280 feet high with an initial velocity of 48 ft/s. The height of
Pani-rosa [81]

Answer:

i hope it helpful

thank you

7 0
3 years ago
Read 2 more answers
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