Which of the following figures are quadrilaterals?

Irina18 [472]

The answer is D (5/4). We go up by 5 and to the side we go 4 in order to get between the points (0,8) and (-4,3). We know it’s rise over run. The rise is 5 because we go up by 5 and the run is 4 because we go to the side 4 times. By looking from left to right at the line, we see it’s a going to be positive. This means the answer is 5/4.

7 0

2 years ago

Read 2 more answers

Imagine a new pasture with grass growing on it. Every day after the seeds have germinated, the number of blades of grass in the

Arisa [49]

Answer:

It took 17 days for the pasture to be one-third covered in grass

Step-by-step explanation:

* Lets explain how to solve the problem

- The number of blades of grass is triple every day

- Consider that there are x blades in the first day

∵ The number of blades of grass is triple every day

∴ The next day the number of blades of grass will be 3x

∴ The formula to find the number of blades of grass after d days is

$x(3)^{d}$

- After 18 days, the entire pasture is completely covered in grass

∵ d = 18

∴ The number of blades of grass = $x(3)^{18}$

- We need to know the the number of days that took for the pasture

to be one-third covered in grass

∵ The number of blades of grass for 1/3 covered = $(\frac{1}{3})x(3)^{18}$

∴ $(\frac{1}{3})x(3)^{18}=x(3)^{d}$

- Remember $\frac{1}{3}=3^{-1}$

∴ $3^{-1}x(3)^{18}=x(3)^{d}$

- Remember we add the power of the same bases when we

multiply them

∴ $x(3)^{-1+18}=x(3)^{d}$ ⇒ divide both sides by x

∴ $(3)^{17}=(3)^{d}$

- Remember if the two bases equal in the equation, then their

powers are equal

∴ d = 17

* It took 17 days for the pasture to be one-third covered in grass

4 0

3 years ago

PLZZZZZ HELP

kari74 [83]

Answer: B

a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side.

Hope this helps!

7 0

3 years ago

How do you determine where f(x)=cos^(-1)(lnx) is continuous?

olga nikolaevna [1]

$\ln x$ is continuous over its domain, all real $x>0$ .

Meanwhile, $\cos^{-1}y$ is defined for real $-1\le y\le1$ .

If $y=\ln x$ , then we have $-1\le \ln x\le1\implies \dfrac1e\le x\le e$ as the domain of $\cos^{-1}(\ln x)$ .

We know that if $f$ and $g$ are continuous functions, then so is the composite function $f\circ g$ .

Both $\cos^{-1}y$ and $\ln x$ are continuous on their domains (excluding the endpoints in the case of $\cos^{-1}y$ ), which means $\cos^{-1}(\ln x)$ is continuous over $\dfrac1e$ .

7 0

3 years ago

Consider the geometric sequence 16, 8, a, 2, b, ... (a) Write down the common

Artist 52 [7]

Find the common ratio by dividing.

16 / 8 = 2

8 / a = 2

2 / b = 2

The common ratio is 2.

Since we need to find the values of a and b, use the common ratio to solve for them.

8 / 2 = 4 (a)

2 / 2 = 1 (b)

Now, we know that first 5 terms.

We can solve for the 8th term using the previous terms and the common ratio.

6th term: 1 / 2 = 0.5

7th term: 0.5 / 2 = 0.25

8th term: 0.25 / 2 = 0.125

Part A: 2

Part B: a = 4, b = 1

Part C: 0.125

Best of Luck!

3 0

3 years ago