2) 60 because it's the one that appear the most
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Answer:
y = 1/4x -2
Step-by-step explanation:
The line rises one unit from -2 to -1 as x changes from 0 to 4. The slope is ...
m = rise/run = 1/4
The y-intercept (b) is where the line crosses the y-axis, at y = -2.
The equation in slope-intercept form is ...
y = mx + b
y = 1/4x -2
From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
Answer:
Solution given:
b=9 base side of isosceles triangle
a=
<span>"Solving for variable 'b'.
Move all terms containing b to the left, all other terms to the right.
Add '-2b' to each side of the equation.
4 + b + -2b = -5 + 2b + -2b
Combine like terms: b + -2b = -1b
4 + -1b = -5 + 2b + -2b
Combine like terms: 2b + -2b = 0
4 + -1b = -5 + 0
4 + -1b = -5
Add '-4' to each side of the equation.
4 + -4 + -1b = -5 + -4
Combine like terms: 4 + -4 = 0
0 + -1b = -5 + -4
-1b = -5 + -4
Combine like terms: -5 + -4 = -9
-1b = -9
Divide each side by '-1'.
b = 9
Simplifying
b = 9"- geteasysolution.com</span>
