F(n)=3n
f(1/3)=3(1/3)
f(1/3)=1
Hope I didn't mess up for your sake
Answer:
x=2 and y=1
Step-by-step explanation:
Rewrite equations:
y=−x+3;y=x−1
Step: Solve
y=−x+3
Step: Substitute−x+3foryiny=x−1:
y=x−1
−x+3=x−1
−x+3+−x=x−1+−x(Add -x to both sides)
−2x+3=−1
−2x+3+−3=−1+−3(Add -3 to both sides)
−2x=−4−2x−2=−4−2
(Divide both sides by -2)
x=2
Step: Substitute2forxiny=−x+3:
y=−x+3
y=−2+3
y=1(Simplify both sides of the equation)
Hope this Helps you :)
Answer:
X=24
Step-by-step explanation:
1. (4x + 11) + (3x + 1) = 180 (Combine like terms)
2. 7x + 12 = 180 (Subtract 12 from both sides)
3. 7x = 168 (Divide both sides by 7)
4. x = 24
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
I believe that answer is B. (The second one)
Hope this helped !!