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stira [4]
3 years ago
8

Please help it’s a pic

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0

Answer:

58°

Step-by-step explanation:

<MQR = <XQL (vertically opposite angles)

28 + 5b = 70 - 2b

28 - 70 = -2b - 5b

-42 = -7b

-42/-7 = b

6 = b

<MQR = 28 + 5b

= 28 + 5(6)

= 28 + 30

= 58°

Tamiku [17]3 years ago
5 0

Answer:

(A)

Step-by-step explanation:

<XQL and <MQR are vertical angles, which means that their measures are equal to each other.

I used the two equations to solve for b.

[see first picture]

When B got solved, I replaced b in MQR's equation with 6 (B = 6), and I got 58, which is option A.

[see second picture]

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abruzzese [7]

Answer:

True

Step-by-step explanation:

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2 years ago
9.3.2 Listed below are body temperatures from five different subjects measured at 8 AM and again at 12 AM. Find the values of d
kotegsom [21]

Answer:

\frac{}{d} = −0.26

s_{d} = 0.4219

Step-by-step explanation:

Given:

Sample1:  98.1  98.8  97.3  97.5  97.9

Sample2: 98.7  99.4  97.7  97.1  98.0

Sample 1           Sample 2              Difference d

98.1                        98.7                       -0.6  

98.8                       99.4                       -0.6

97.3                        97.7                       -0.4

97.5                        97.1                         0.4

97.9                        98.0                       -0.1

To find:

Find the values of \frac{}{d} and s_{d}

d overbar ( \frac{}{d})  is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5

\frac{}{d} = ∑d/n

 = (−0.6 −0.6 −0.4 +0.4 −0.1) / 5

 = −1.3 / 5

\frac{}{d} = −0.26

s Subscript d is the sample standard deviation of the difference which is calculated as following:

s_{d} = √∑(d_{i} - \frac{}{d})²/ n-1

s_{d} =

√ (-0.6 - (-0.26))^{2} + (-0.6 - (-0.26))^{2} + (-0.4 - (-0.26))^{2} + (0.4-(-0.26))^{2} + (-0.1 - (-0.26))^{2} / 5-1

    =  √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −  

                                                                     (−0.26))² + (−0.1 − (−0.26))² / 5−1

=  \sqrt{\frac{0.1156 +  0.1156 + 0.0196 + 0.4356 + 0.0256}{4}  }

= \sqrt{\frac{0.712}{4} }

= \sqrt{0.178}

= 0.4219

s_{d} = 0.4219

Subscript d ​represent

μ_{d} represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.

3 0
3 years ago
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Step-by-step explanation:

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