Which equation can be used to find the answer?

ss7ja [257]

8 is the answer ................

8 0

3 years ago

1. The prism-shaped roof has equilateral triangular bases. Create an equation that models the height of one of the roof's triang

Mandarinka [93]

1. Check picture 1. Let the one side of the triangle be a, drop one perpendicular, CD. Then triangle ADB is a right triangle, with hypothenuse a and one side equal to 1/2a. By the Pythegorean theorem, as shown in the picture, the height is $\frac{ \sqrt{3} }{2} a$

2. if a a=25 ft, then the height is $\frac{ \sqrt{3} }{2} a=\frac{ \sqrt{3} }{2} *25= \frac{1.732}{2}*25= 21. 7$ (ft)

3. consider picture 2. Let the length of the roof be l feet.

one side of the prism (the roof) is a rectangle with dimensions a and l, so the area of one side is a*l
the lateral Area of the roof is 3a*l

the area of the equilateral surfaces is $2*( \frac{1}{2} *a* \frac{ \sqrt{3} }{2}a )=\frac{ \sqrt{3} }{2} a^{2}$

so the total area of the roof is $\frac{ \sqrt{3} }{2} a^{2} +3al$

4. The total area was the 2 triangular surfaces + the 3 equal lateral rectangular surfaces. Now instead of 3 lateral triangular surfaces, we have 2.
So the total area found previously will be decreased by al

5. so the area now is $\frac{ \sqrt{3} }{2} a^{2} +2al$

6. now a=25 and l=2a=50

Area= $\frac{ \sqrt{3} }{2} a^{2} +2al=\frac{ \sqrt{3} }{2} * 25^{2}+2*25*50=25 ^{2} (\frac{ \sqrt{3} }{2} +4)=625*4.866$

=3041.3 (ft squared)

7 0

3 years ago

Read 2 more answers

What is 5/11 in decimal form? (round your answer to the nearest hundredth.)?

natita [175]

5/11 in decimal form is .45

4 0

3 years ago

A rectangular park is 150 yards on one side and 125 yards on the other.

Ket [755]

So, there is a rectangular park with longer side (length) 150 yards and shorter side (width) 125 yards.

so walking around the rectangular park once is like covering the Perimeter (p) of the rectangular park.

So, lets find the perimeter of the park.
Perimeter of rectangle = 2 ( l + w)
= 2 ( 150 + 125 )
= 2 * 275
= 550 yards

Now, walking around the park two times is like doubling the Perimeter of the rectangle. So, when Debbie walks around the park 2 times, he covers the perimeter of the rectangular field twice.

i.e. Debbie walked 2 * Perimeter
= 2 * 550
= 1100 yards

Now, If Debbie wanted to walk 1,000,000 yards, she has to walk the rectangular park (1,000,000 / the Perimeter of the park)
i.e. 1,000,000 / 550
= 1818.18 times

So,
(a) she walks 1100 yards
(b) She have to walk 1818.18 times

4 0

3 years ago

What is the mass of a solid ball of iron with a radius equal to 18 cm if it is known that the density of iron is 7800 kg/m

Shtirlitz [24]

Answer:

60.6528 kg

Step-by-step explanation:

Assuming the solid ball of iron is a sphere with a radius of 18 cm (or 0.18 m), we can compute the volume of the sphere:

$V=\frac{4}{3}\pi r^3\\\\V=\frac{4}{3}\pi (\frac{18}{100})^3\\\\V=\frac{4}{3}\pi (0.005832)\\\\V=0.007776$

Therefore, the volume of the solid ball is 0.007776 m³

Since we know that density is mass/volume, then we can find the mass of the iron:

$\rho=\frac{mass}{volume}\\ \\7800\: kg/m^3=\frac{mass}{0.007776\: m^3}\\\\mass=60.6528\:kg$

Thus, the mass of the solid ball of iron is 60.6528 kg

8 0

2 years ago