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Ahat [919]
3 years ago
9

HELP PLEASEE Multiply negative 1 over 6 multiplied by negative 1 over 5

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0
Negative 1 over 11
negative 1 over 30
1 over 30
1 over 11
-1/6*-1/5 = 1/30
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If a² + b² = z and ab = y, which of the following is equivalent to 4z + 8y? Show all the steps.
Ivenika [448]

Answer:

The answer to your question is:       (2a + 2b)²

Step-by-step explanation:

a² + b² = z

ab = y

Which is equivalent to 4z + 8y ?

Substitution

                                     4(a² + b²) + 8(ab)

Simplify                        4a² + 4b² + 8ab

Order                            4a² + 8ab + 4b²       It's a perfect square trynomial

Factorize                     (2a + 2b)²

7 0
3 years ago
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How do you find the missing variables in this problem please help
andrew-mc [135]

Answer:

x = 55, y = 70, z = 125

Step-by-step explanation:

125 and x are adjacent angles and are supplementary, then

x = 180 - 125 = 55

The triangle is isosceles ( 2 congruent sides ) thus the base angles are congruent, both 55

The sum of the 3 angles in the triangle = 180° , thus

y = 180 - (55 + 55) = 180 - 110 = 70

55 and z are adjacent and supplementary, so

z = 180 - 55 = 125

4 0
3 years ago
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Add the two expressions.
Vladimir79 [104]
Your answer will be 3.7w-2
8 0
3 years ago
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Complete the equation describing how x and y are related.
Sav [38]

Answer: The "?" would equal 1.

Step-by-step explanation: This is simply a line with a slope of 1 and a y-intercept of zero.

5 0
3 years ago
For the problem 1/5g- 1/10- g + 1 3/10g -1/10, Tyson created an equivalent expression using the following steps. 1/5g+-1g+1 3/10
professor190 [17]

The true statements are:

  • Tyson's expression is not equivalent to the original expression
  • The equivalent expression is:\frac{1}{2}g- \frac 1{5}

<h3>What are equivalent expressions?</h3>

Equivalent expressions are expressions that have equal values

The original expression is given as:

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10}

Collect like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac 15g - g + 1 \frac{3}{10}g- \frac 1{10}  -\frac{1}{10}

Evaluate the like terms

\frac 15g- \frac 1{10}- g + 1 \frac{3}{10}g -\frac{1}{10} = \frac{1}{2}g- \frac 1{5}

Tyler's equivalent expression is given as:

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10}

Collect like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = \frac15g-g+ 1 \frac3{10}g-\frac 45g-\frac 1{10}+1 \frac{1}{10}

Evaluate the like terms

\frac15g-g+ 1 \frac3{10}g-\frac 1{10}-\frac 45g+1 \frac{1}{10} = -\frac 3{10}g

The simplified expressions of the original expression, and Tyson's equivalent expressions are not equal.

Hence, Tyson's expression is not equivalent to the original expression

Read more about equivalent expressions at:

brainly.com/question/9603710

3 0
2 years ago
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