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Sedbober [7]
3 years ago
9

Suppose you have 100 ft of string to rope off a rectangular section for a bake sale at a school Fair. The function A=x^2+50x giv

es the area of the section in square feet, where x is the width in feet. What width gives you the maximum area you can rope off? What is the maximum area? What is the range of the function?
Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

Therefore the width is 25 feet for getting maximum area.

The maximum area of the rectangle is 625 square feet.

Therefore the range is 0≤A≤625.

Step-by-step explanation:

Given function is

A = - x²+50x

We know that ,

If y = ax²+bx+c

For the maximum x=-\frac{b}{2a}

Here a = -1 , b= 50 and c=0

Therefore the width x= -\frac{50}{2.(-1)} = 25

Therefore the width is 25 feet for getting maximum area.

The maximum area =[ -(25)²+50.25] square feet

                                 = 625 square feet

The area can not be negative and maximum area is 625 square feet.

Therefore the range is 0≤A≤625.

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Add the sum of 1 and one nineth part of 72 to the sum of 72 and one fourth of 72.​
meriva

Answer:

99

Step-by-step explanation:

1/9 of 72 = 8

1/4 of 72 = 18

1 + 8 = 9

72 + 18 = 90

90 + 9 = 99

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

3 0
3 years ago
Write the equation for a line that passes through the point (-8,2) and is parallel to 5x-4y=4. Enter your equation in slope inte
Lana71 [14]

Answer:

y = 5/4x + 12

Step-by-step explanation:

5x - 4y = 4

-4y = -5x + 4

y = (-5x + 4)/-4

y = 5/4x - 1

Parallel Slope ---> m = 5/4

(-8, 2)

y = mx + b

2 = 5/4(-8) + b

2 = 5 * -2 + b

2 = -10 + b

12 = b

b = 12

y = 5/4x + 12      <---- This is the answer

Hope this helps!

3 0
3 years ago
Please help seems easy just can’t figure out the answer
madreJ [45]

Answer:

b is 125

Step-by-step explanation:

8 0
4 years ago
A motorboat travels 168 kilometers in 4 hours going upstream. It travels 280 kilometers going downstream in the same amount of t
Grace [21]

Answer:

The speed of the boat is 56 km/hr

The rate of the current is 14 km/hr

Step-by-step explanation:

We are given the following;

  • Distance traveled upstream = 168 km
  • Time taken to travel upstream = 4 hours
  • Distance traveled down stream = 280 km
  • Time taken down stream = 4 hours

We are required to determine the speed of the boat in still water and the speed of the current.

We are going to take;

Speed of the boat as = x km/hr

Rate of flow of current = y km/hr

We can determine the speed of the boat upstream;

Speed = Distance ÷ time

               = 168 km ÷ 4 hours

               = 42 km/hr

But, the speed upstream is given by (x - y) km/hr

Therefore; ( x-y) km/hr = 42 km/hr ......................... Eqn 1

Speed of the boat down stream

    speed = 280 km ÷ 4 hours

                = 70 km/hr

But, the speed downstream is given by (x+y) km/hr

Therefore, x+y km/hr = 70 km/hr ........................... Eqn 2

Solving Eqn 1 and Eqn 2 simultaneously;

x - y = 42

x + y = 70

Eliminating x

-2y = - 28

    y = 14 km/hr

Solving for x,

x = 42 + y

   = 42 + 14

   = 56 km/hr

Therefore, the speed of the boat is 56 km/hr while the rate of the current is 14 km/hr

8 0
4 years ago
(Pre-Algebra)<br><br> PLEASE HELP ME WITH THE QUESTIONS ABOVE!
faust18 [17]
A) 460 ≥9.50h+60

B) the minimum of hours Jessie can work is about 42 hours.
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