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Sedbober [7]
3 years ago
9

Suppose you have 100 ft of string to rope off a rectangular section for a bake sale at a school Fair. The function A=x^2+50x giv

es the area of the section in square feet, where x is the width in feet. What width gives you the maximum area you can rope off? What is the maximum area? What is the range of the function?
Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

Therefore the width is 25 feet for getting maximum area.

The maximum area of the rectangle is 625 square feet.

Therefore the range is 0≤A≤625.

Step-by-step explanation:

Given function is

A = - x²+50x

We know that ,

If y = ax²+bx+c

For the maximum x=-\frac{b}{2a}

Here a = -1 , b= 50 and c=0

Therefore the width x= -\frac{50}{2.(-1)} = 25

Therefore the width is 25 feet for getting maximum area.

The maximum area =[ -(25)²+50.25] square feet

                                 = 625 square feet

The area can not be negative and maximum area is 625 square feet.

Therefore the range is 0≤A≤625.

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Step-by-step explanation:

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Answer:

<em>The solution of the equation </em>

<em>( 0.4 ,-3)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given system of equations

                                  10 x+3 y = −5 ...(i)

                                 - 5 x - 4 y = 10 ...(ii)

Multiply (i) with '5'

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Multiply (ii) with '10'

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<u><em>Step(ii)</em></u>:-

Solving (iii) and (iv)

        50 x + 15 y =- 25

     <u>  - 50 x - 40 y =100</u>

                - 25 y = 75

Dividing ' - 25' on both sides, we get

               <em>    y = -3</em>

<em>substitute y = -3 in equation (i) , we get</em>

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                10 x = -5 + 9

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                 <em>  x =  0.4  </em>

<u><em>Final answer</em></u>:-

 <em>The solution of the equation   ( 0.4 ,-3)</em>

           

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