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Soloha48 [4]
3 years ago
6

20 points! Please help!!

Mathematics
2 answers:
astraxan [27]3 years ago
5 0
The answe is 41... 65 minus 24
ANEK [815]3 years ago
5 0
In order to find the interquartile range you must subtract the highest number from the lowest number
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Helppppp! what is 2+6????
yaroslaw [1]

Answer:

8...I want these points lol

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
For the graph shown to the right, find (a) AB to the nearest tenth and (b) the coordinates of the midpoint of AB.
Shkiper50 [21]
AB =

\sqrt{( {4 -  (- 2))}^{2}  +  {( - 5 + 3)}^{2} }  =  \sqrt{40}  = 6.3
The midpoint os segment AB =

(( \frac{ - 2 + 4}{2} ) = the \: x \: coordinate \: of \: the \: midpoint \\  \\ ( \frac{ - 3 - 5}{2})) = the \: y \: coordinate \: of \: the \: midpoint
The midpoint is:

(1,-4)
8 0
3 years ago
3x -4y= -20 -x +2y =10 whats the value of y
Anni [7]
3x-4y=10
-20-x+2y=10 then -30+2y=x now plug this in the other equation:
3(-30+2y)-4y=10
-90+6y-4y=10
2y=100
y=50
4 0
2 years ago
Use the quadratic function f(x) = 2x^2 + 4x - 15. Find any x intercepts.
8_murik_8 [283]

So for this function we will be using the quadratic formula, which is x=\frac{-b+\sqrt{b^2-4ac}}{2a},\frac{-b-\sqrt{b^2-4ac}}{2a} , to solve. a = x^2 coefficient, b = x coefficient, and c = constant. Using our equation, we can solve for the zeros (x-intercepts) as such:

x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

6 0
3 years ago
Find the product (x + 4)​
vova2212 [387]

Answer:

4x

Step-by-step explanation:

It would be 4x because you have no value given of the variable "X"

therefore, your answer would just be adding the x to the 4 making it 4x

hope this helped!

6 0
2 years ago
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