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BaLLatris [955]
3 years ago
9

I'm not too sure on this one​

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0
I want to help, but I forgot how to do this. I’m sooo sorry D:
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5
uranmaximum [27]

Answer:

ok....let me try .....

  • ohhhh leave it. gu

<h2>..ok bro....sorry don't be angry <em><u>b</u></em><em><u>j</u></em><em><u>h</u></em><em><u>u</u></em><em><u>j</u></em><em><u>j</u></em></h2>
6 0
2 years ago
When babies are born, their lengths are recorded. Maddy is 18 1/2 inches. Her twin Alex, is 20 3/4 inches. How much longer is Ma
Furkat [3]

Answer:

Alex is 2 1/4 inches longer than Maddy

Step-by-step explanation:

Alex is longer than Maddy

20 3/4 - 18 1/2

Get a common denominator

20 3/4 - 18  2/4

2 1/4

Alex is 2 1/4 inches longer than Maddy

Maddy is -2 1/4 inches longer than Alex

7 0
3 years ago
Read 2 more answers
Answer ASAP please, Will give brainliest.
nikdorinn [45]

Answer:

see below

Step-by-step explanation:

The measure of a minor arc is the same as the angle that forms it.

1. Since ∠GBJ = 90°, the answer is 90°.

2. ∠HBI = 180° - 151° = 29° so the answer is 29°.

3. ∠HBJ = 180° so the answer is 180°.

4. The reflex angle ∠GBI = 90 + 151 = 241° so the answer is 241°/

5. Since ∠GBJ = 90°, the reflex angle ∠GBJ = 360 - 90 = 270° so the answer is 270°.

6. ∠GBH = 180 - 90 = 90° so the reflex angle ∠GBH = 360 - 90 = 270° so the answer is 270°.

4 0
3 years ago
Help BRAINLIEST........
storchak [24]

Answer:

5.52 is the length of wire

8 0
2 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
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