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BaLLatris [955]
3 years ago
9

I'm not too sure on this one​

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0
I want to help, but I forgot how to do this. I’m sooo sorry D:
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Please Help!<br> Factor the following trinomial<br> <img src="https://tex.z-dn.net/?f=9x%5E2-24x%2B16" id="TexFormula1" title="9
AlexFokin [52]

\huge\colorbox{pink}{Hey \: panda!}

The answer=>

For this,we need to know what's Middle splitting method

  • In order to factorize x² + bx + c we have to find numbers p and q such that p + q = b and pq = c. After finding p and q, we split the middle term in the quadratic as <em><u>px + qx and</u></em> get desired factors by grouping the terms.

Step-by-step explanation:

9x {}^{2}  - 24x + 16 \\  =  > 9x {}^{2}  - 12x - 12x + 16 \\  =  > 3x(3x - 4) - 4(3x - 4) \\  =  > (3x - 4)(3x - 4) \\ so... \\ x = eitherway \: 4

i.e

Alpha= Beta = 4

5 0
3 years ago
Read 2 more answers
What is the next letter b a d e h g k
aivan3 [116]
Abcdefghijklmnopqrstuvwxyz

ok

b to a
goes back 1 letter

then b to d
skips 3 letters forward

then d to e
1 forward

e to h
skips 3 forward

h to g
goes 1 back

g to k
goes 3 forward

pattern seems to be
1back, 3 forward, 1 forward, 3 forward, repeat
so we are at 3 forward after than 1 back, so the next one is 1 forward

1 forward from k is l

the next letter is L
8 0
4 years ago
The value of a car depreciates by 35% per year. Work out the current value of a car bought 2 years ago for £20000
Rzqust [24]

First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;

Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.

6 0
3 years ago
How do you round 1,995,298 to the nearest 10,000
xxTIMURxx [149]
2,000,000 is the answer

5 0
3 years ago
Which polynomial function has a leading coefficient of 1 and roots (7 i) and (5 – i) with multiplicity 1? f(x) = (x 7)(x – i)(x
Nuetrik [128]

It looks like you might have intended to say the roots are 7 + i and 5 - i, judging by the extra space between 7 and i.

The simplest polynomial with these characteristics would be

f(x) = (x - (7 + i)) (x - (5 - i))

but seeing as each of the options appears to be a quartic polynomial, I suspect f(x) is also supposed to have only real coefficients. In that case, we need to pair up any complex root with its conjugate to "complete" f(x). We end up with

f(x) = (x - (7 + i)) (x - (7 - i)) (x - (5 - i)) (x - (5 + i))

which appears to most closely resemble the third option. Upon expanding, we see f(x) does indeed have real coefficients:

f(x) = (x^2 - (7^2 - i^2)) (x^2 - (5^2 - i^2)) = (x^2 - 8) (x^2 - 6) = x^4 - 14x^2 + 48

5 0
2 years ago
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