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algol [13]
3 years ago
14

Chris rented truck for one day. There was a base fee of $16.99, and there was an additional charge of 93 cents for each mile

Mathematics
1 answer:
const2013 [10]3 years ago
8 0

Answer:

226 miles

Step-by-step explanation:

Sorry this question couldn't be answered sooner, but here is the answer now:

In order to solve this, we must first subtract the total Chris paid by the base fee:

227.17 - 16.99 = 210.18

Then, we divide this number by 0.93:

210.18 / 0.93 = 226

So, Chris drove the truck 226 miles

Hope this helps :)

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Two lines that intersect to form right angle are called
Sergio039 [100]

Answer:

perpendicular

Step-by-step explanation:

When 2 lines intersect at any point, not just in the middle of each (that has nothing to do with it), and they meet to form right angles, the lines are perpendicular to one another and their slopes are opposite reciprocals.

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En un consultorio medico infanfil se consultas mensualmente a 160 pacientes si la razon de cada 8 paciente 5 son niñas A ¿cuanto
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Answer: 60 of the patients are boys.

Step-by-step explanation: According to what is described, 5 in 8 patients are girls, then: 8 - 5 = 3, i.e., 3 in 8 are boys.

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3 years ago
Study island Jack Russell high school 96 students plan on going to end in State College and 58 students plan on going to an out
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Answer:

48:29

Step-by-step explanation:

So lets find the ratio without simplest form: the ratio is 96:58

When writing the ratio we write the one mention first

Now lets write it in simplest form practically reducing it to its lowest term

\frac{96}{58}( we first write it as a fraction)

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So the answer is 48:29

HOPE IT HELPED

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Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
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