There are 25 $10 bills and 11 $20 bills.
Step-by-step explanation:
Given,
Worth of proceeds from garage = $470
Let,
x be the number of $10 bills
y be the number of $20 bills.
According to given situation;
10x+20y=470 Eqn 1
x = y+14 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 30

Putting y=11 in Eqn 2

There are 25 $10 bills and 11 $20 bills.
Keywords: linear equation, substitution method
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Answer: r = 11
Step-by-step explanation:
We know that the point (-2, r) lies on the graph of:
2*x + y = 7.
Then, if we that point is on the graph of the equation, we can replace the values and we will have:
2*(-2) + r = 7
and now we solve this for r-
-4 + r = 7
r = 7 + 4 = 11
r = 11
The answer is 3x+15
You multiply the x and 5 by 3 to get 3x and 15
Answer:
A
Step-by-step explanation: