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Klio2033 [76]
2 years ago
11

Divide. 51.75 ÷ 15 3.45 34.5 345 I don't know.

Mathematics
1 answer:
Mumz [18]2 years ago
3 0

Answer:

3.45

Step-by-step explanation:

Do long division to get your answer, but instead of division you can just multiply 15 x 3.45 and you'll get 51.75.

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This is a proportion. What is the value of X?
Verizon [17]

Answer:

x = 15 or x = - \frac{2}{5}

Step-by-step explanation:

Cross- multiplying gives

(14x + 6)(17x + 5) = 9x(27x + 11) ( expanding factors )

238x² + 172x + 30 = 243x² + 99x

rearrange into standard form : ax² + bx + c = 0

5x² - 73x - 30 = 0 ← in standard form

consider the factors of the product 5 × - 30 = - 150 which sum to the coefficient of the x-term (- 73 )

the factors are - 75 and + 2

Use these factors to split the middle term

5x² - 75x + 2x - 30 = 0 ( factor by grouping )

5x(x - 15) + 2(x - 15) = 0 ← take out the factor (x - 15)

(x - 15)(5x + 2) = 0

equate each factor to zero and solve for x

x - 15 = 0 ⇒ x = 15

5x + 2 = 0 ⇒ x = - \frac{2}{5}


7 0
2 years ago
A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If
musickatia [10]

Answer:

a. The test statistic for this hypothesis would be z=1.71

b. Critical value at α = 0.10: z=1.282

c. Reject H0, the television network should not keep its current lineup.

d. H0: p ≤ 0.50; HA: p > 0.50

Step-by-step explanation:

We have to performa an hypothesis test on a proportion.

The claim is that the proportion of viewers that prefer the new show is bigger than 50% (meaning that most viewers prefer the new show).

The null hypothesis will state that both shows have the same proportion.

Then, the null and alternative hypothesis are:

H_0: \pi\leq0.50\\\\H_a: \pi>0.5

The sample proportion is p=0.53

p=X/n=438/827=0.53

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.5*0.5}{827}}= 0.017

Then, the z-statistic can be calculated as:

z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.50-0.5/827}{0.017}=\dfrac{ 0.029 }{0.017} =1.706

The critical value for a right tailed test at a significance level of 0.10 is zc=1.282. This value can be looked up in a standard normal distribution table.

As the statistic is bigger than the critical value, it lies in the rejection region. The null hypothesis is rejected. There is evidence to support the claim that the proportion of viewers which support the new show is larger than 0.50.

4 0
3 years ago
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Step-by-step explanation:

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