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alexandr402 [8]
3 years ago
10

I need help I’m bad at math

Mathematics
1 answer:
Alina [70]3 years ago
5 0
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
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The sum of 69 and 42 is five more than the difference of 146 and a number. Calculate the value of the unknown number.
Len [333]
As an equation, we have:
69+42=5+(146-x)

You just have to simplify:

111=5+(146-x)
106=146-x
-40=-x
40=x

Your unknown number is 40
5 0
3 years ago
Solve 2x – 7 > 11.
BaLLatris [955]

Answer:

x > 9

Step-by-step explanation:

2x - 7 > 11

2x > 18

x > 9

5 0
3 years ago
can you help me evaluate this: 7m + 14m - 6n - 5n + 2m. why do you add 6n with 5n instead of subtract?
Mademuasel [1]

Step-by-step explanation:

The reason is because it is not just 6 it is - 6 so when there are two negative numbers they don't subtract they add if it was 6n then it was to be subtracted

21m - 11n + 2m

23m - 11n

6 0
3 years ago
if there are 2040 seats in a section of a stadium, 20 seats in the first row, and 4 more seats in each row, how many rows are th
Lorico [155]


2040 = n/2(20+(n-1)4)

4080 = n(20+4n-4)

4080= 20n +4n^2 -4n

1020 = 4n + n^2

n^2 +4n -1020 =0

use common formula (can't write out so just look at answers. sorry)

which gives answers of n=-34 and n=30. since n can only be positive, n=30 so there are 30 rows. I liked that challenge

5 0
3 years ago
Read 2 more answers
Which pair of complex factors results in a real number product? 15(–15i) 3i(1 – 3i) (8 + 20i)(–8 – 20i) (4 + 7i)(4 – 7i)
photoshop1234 [79]

Answer:

(4 + 7i)(4 – 7i)

Step-by-step explanation:

This pair will produce a real answer because they are complex conjugates.

Complex conjugates ( a+bi) (a-bi)  when multiplied together form a real number ( a^2 + b^2)

6 0
3 years ago
Read 2 more answers
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