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alexandr402 [8]
3 years ago
10

I need help I’m bad at math

Mathematics
1 answer:
Alina [70]3 years ago
5 0
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
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Juliette [100K]
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3 years ago
How much would you need to deposit in an account now in order to have $4000 in the account in 10 years? Assume the account earns
gogolik [260]

Answer:

  $2355.06

Step-by-step explanation:

Use the compound interest formula, filling in the numbers you know. Then solve for the number you don't know.

  A = P(1 +r/n)^(nt)

where A is the account balance, P is the amount invested, r is the annual rate, n is the number of times per year interest is compounded, and t is the number of years.

Filling in the given values, we have ...

  4000 = P(1 +.053/52)^(52·10) = P(1.6984738)

  P = 4000/1.6984738 ≈ 2355.06

You would need to deposit $2355.06 in order to have $4000 in 10 years.

5 0
3 years ago
What is 4 to the 7th power ?
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5 0
3 years ago
- The capacity of the aquarium is 9000 mL.<br>What is the height of the aquarium?<br>​
KatRina [158]
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4 0
3 years ago
A binomial probability experiment is conducted with the given parameters. Compute the probability of x successes in the n indepe
-Dominant- [34]

Answer: 0.0031

Step-by-step explanation:

Binomial distribution formula :-

P(x)=^nC_xp^x(1-p)^{n-x}, where P(x) is the probability of x successes in the n independent trials of the experiment and p is the probability of success.

Given : A binomial probability experiment is conducted with the given parameters.

n=9,\ p=0.8,\ x\leq3

Now, P(x\leq3)=P(3)+P(2)+P(1)+P(0)

=^9C_3(0.8)^3(1-0.8)^{9-3}+^9C_2(0.8)^2(1-0.8)^{9-2}+^9C_1(0.8)^1(1-0.8)^{9-1}+^9C_0(0.8)^0(1-0.8)^9\\\\=\dfrac{9!}{3!6!}(0.8)^3(0.2)^6+\dfrac{9!}{2!7!}(0.8)^2(0.2)^7+\dfrac{9!}{1!8!}(0.8)(0.2)^8+\dfrac{9!}{0!9!}(0.2)^9=0.003066368\approx0.0031

Hence,  P(x\leq3)=0.0031

8 0
3 years ago
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