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3 years ago

If y = 9 and x = 12, what additional information is necessary to show that

1 answer:

5 0

Answer

one of the angles opposite to side x or y.

Explanation
We use the sine rule to you the postulate SAS.

x/sinX = y/sinY
where x and y are the sides of angles X and Y respectively.

You might be interested in

The perimeter of a rectangular banner is 72 inches. The width of the banner is 1/3 its length. What is the area of the banner?

muminat

Answer:

144

Step-by-step explanation:

If you multiply 4 by 12, then add 100, you get 144 which is the area.

4 0

2 years ago

B) Let g(x) =x/2sqrt(36-x^2)+18sin^-1(x/6)<br><br> Find g'(x) =

jolli1 [7]

I suppose you mean

$g(x) = \dfrac x{2\sqrt{36-x^2}} + 18\sin^{-1}\left(\dfrac x6\right)$

Differentiate one term at a time.

Rewrite the first term as

$\dfrac x{2\sqrt{36-x^2}} = \dfrac12 x(36-x^2)^{-1/2}$

Then the product rule says

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 x' (36-x^2)^{-1/2} + \dfrac12 x \left((36-x^2)^{-1/2}\right)'$

Then with the power and chain rules,

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12\left(-\dfrac12\right) x (36-x^2)^{-3/2}(36-x^2)' \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} - \dfrac14 x (36-x^2)^{-3/2} (-2x) \\\\ \left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-1/2} + \dfrac12 x^2 (36-x^2)^{-3/2}$

Simplify this a bit by factoring out $\frac12 (36-x^2)^{-3/2}$ :

$\left(\dfrac12 x(36-x^2)^{-1/2}\right)' = \dfrac12 (36-x^2)^{-3/2} \left((36-x^2) + x^2\right) = 18 (36-x^2)^{-3/2}$

For the second term, recall that

$\left(\sin^{-1}(x)\right)' = \dfrac1{\sqrt{1-x^2}}$

Then by the chain rule,

$\left(18\sin^{-1}\left(\dfrac x6\right)\right)' = 18 \left(\sin^{-1}\left(\dfrac x6\right)\right)' \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac x6\right)'}{\sqrt{1 - \left(\frac x6\right)^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18\left(\frac16\right)}{\sqrt{1 - \frac{x^2}{36}}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{3}{\frac16\sqrt{36 - x^2}} \\\\ \left(18\sin^{-1}\left(\dfrac x6\right)\right)' = \dfrac{18}{\sqrt{36 - x^2}} = 18 (36-x^2)^{-1/2}$

So we have

$g'(x) = 18 (36-x^2)^{-3/2} + 18 (36-x^2)^{-1/2}$

and we can simplify this by factoring out $18(36-x^2)^{-3/2}$ to end up with

$g'(x) = 18(36-x^2)^{-3/2} \left(1 + (36-x^2)\right) = \boxed{18 (36 - x^2)^{-3/2} (37-x^2)}$

5 0

2 years ago

Collins has a part-time job as a dog walker. The table below shows the amount of money Collins earned for different numbers of h

kondor19780726 [428]

Answer:

See below.

Step-by-step explanation:

Part A:

For Dog walking, he earns $30 for 5 hours of work.

He earns $36 for 6 hours of work.

$30/5 hours = $6/hour

$36/6 hours = $6/hour

He earns $6/hour dog walking.

For 8 hours, he earns 8 hours * $6/hour = $48

To earn $66, he works 66/6 = 11 hours.

5 30

6 36

8 48

11 66

Part B:

He earns $7/hour for yard work, so multiply the number of hours by 7 to find the money he earns.

Table for yard work

Hours Money

5 $35

6 $42

8 $56

Part C:

For 5 hours, he earns $35 for yard work and $30 as a dog walker.

$35 - $30 = $5

3 0

3 years ago

What is the polar form of 7 StartRoot 3 EndRoot minus 7 i?

ololo11 [35]

Answer:

14(cos(330 degrees) + i sin(330 degrees))

option D

Step-by-step explanation:

edge 2020

3 0

3 years ago

A square is cut in half on the diagonal creating two equal triangles each triangle has an area of 0.72 square units what is the

Katyanochek1 [597]

In a square all 4 sides are equal, so when you cut it along the diagonal to make a triangle, both the base and the height of the triangle would be the same.

The area of a triangle is found by the formula 1/2 x base x height

Since the base and height are the same the formula becomes Area = 1/2 x S^2 ( where S is the length of a side).

The area is given as 0.72 square units.

Now you have 0.72 = 1/2 x S^2

First multiply both sides by 2:

1.44 = S^2

To find S, take the square root of both sides:

S = √1.44

S = 1.2

The side length is 1.2 units.

7 0

3 years ago