Answer: No, because the –1 in the numerator and denominator is not a common factor and cannot be canceled.
Step-by-step explanation:
Since, the given expression,
![\frac{x^3-1}{x^2-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E3-1%7D%7Bx%5E2-1%7D)
= ![\frac{(x-1)(x^2+x+1)}{(x+1)(x-1)}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x-1%29%28x%5E2%2Bx%2B1%29%7D%7B%28x%2B1%29%28x-1%29%7D)
= ![\frac{x^2+x+1}{x+1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E2%2Bx%2B1%7D%7Bx%2B1%7D)
Thus we can not further simplify the above expression.
Because, There is not any common factor in the numerator and denominator.
Thus, Option C) is correct.
Answer:
Fiona made her error in : Step 2.
Answer:
![s = 6 {x}^{2} \\ {x }^{2} = \frac{s}{6} \\ x = + - \sqrt{ \frac{s}{6} } \\ x = \frac{ \sqrt{s} \times \sqrt{6} }{ \sqrt{6} \times \sqrt{6} } \\ x = \frac{ + - \sqrt{6s} }{6}](https://tex.z-dn.net/?f=s%20%3D%206%20%7Bx%7D%5E%7B2%7D%20%20%5C%5C%20%20%7Bx%20%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7Bs%7D%7B6%7D%20%20%5C%5C%20x%20%3D%20%20%2B%20%20-%20%20%5Csqrt%7B%20%5Cfrac%7Bs%7D%7B6%7D%20%7D%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7Bs%7D%20%5Ctimes%20%20%20%5Csqrt%7B6%7D%20%7D%7B%20%5Csqrt%7B6%7D%20%5Ctimes%20%20%20%5Csqrt%7B6%7D%20%20%7D%20%20%5C%5C%20x%20%3D%20%20%20%5Cfrac%7B%20%20%2B%20%20-%20%5Csqrt%7B6s%7D%20%7D%7B6%7D%20)
the answer is 4 th option
Answer:
11/12
Step-by-step explanation:
2 3/4=11/4
1/3*11/4=11/12