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MAXImum [283]
3 years ago
14

Create three problems that require you to solve each using each of the trig ratios (one problem where you will use sine, one pro

blem where you will use tangent and one problem where you will use cosine) and then solve each problem, show all your work.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
See the attached image for the drawings of the problems. The figures are not to scale. The decimal values in each figure are approximate to one decimal place.

----------------------------------------------

Focus on Figure 1

sin(angle) = opposite/hypotenuse
sin(A) = BC/AC
sin(36) = 13.2/x
x*sin(36) = 13.2
x = 13.2/sin(36)
x = 13.2/0.58778525229248 <<-- make sure calc is in degree mode
x = 22.4571813404936
x = 22.5
This value is approximate (rounded to one decimal place)

----------------------------------------------

Move onto Figure 2

cos(angle) = adjacent/hypotenuse
cos(D) = DE/FD
cos(50) = y/57.4
57.4*cos(50) = y
y = 57.4*cos(50)
y = 57.4*0.64278760968653
y = 36.8960087960069
y = 36.9
This value is approximate (rounded to one decimal place)

----------------------------------------------

Finally, move onto Figure 3

tan(angle) = opposite/adjacent
tan(G) = JH/GH
tan(18) = z/10
10*tan(18) = z
z = 10*tan(18)
z = 10*0.3249196962329
z = 3.249196962329
z = 3.2
This value is approximate (rounded to one decimal place)

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

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2 years ago
What 2 numbers equal -36 when multiplied together but equal 0 when added together?
Lelu [443]
You can do that using  +6  and  -6 .

(6) · (-6)  =  - 36

(6) + (-6)  =  0
7 0
4 years ago
a yard width is 2 less than it's length. If the perimeter of the yard is 20 feet determine the length and the width of the yard
Arte-miy333 [17]

Answer:

The length is 6 feet and the width is 4 feet

Step-by-step explanation:

Let x represent the length of the yard

The width can be represented by x - 2, since it is 2 less than the length.

Use the perimeter formula, P = 2l + 2w, where l is the length and w is width

Plug in the expressions and perimeter:

20 = 2x + 2(x - 2)

Solve for x:

20 = 2x + 2x - 4

20 = 4x - 4

24 = 4x

6 = x

So, the length is 6. Plug this into x - 2 to find the width

x - 2

6 - 2

= 4

So, the length is 6 feet and the width is 4 feet

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Round 147.667 &amp; 142.5 to the nearest cent.
Travka [436]

Answer:

147.67 and 142.50

Step-by-step explanation:

Cents are only two digits after the decimal, aka hundredths. So, you have to round each number to the hundredth.

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What is the first step to solve this equation 4m=44
son4ous [18]

Answer: H

The first step is dividing 4 from both sides to find what m equals. By the way, its the <u>only</u> step :D

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