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MAXImum [283]
3 years ago
14

Create three problems that require you to solve each using each of the trig ratios (one problem where you will use sine, one pro

blem where you will use tangent and one problem where you will use cosine) and then solve each problem, show all your work.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0
See the attached image for the drawings of the problems. The figures are not to scale. The decimal values in each figure are approximate to one decimal place.

----------------------------------------------

Focus on Figure 1

sin(angle) = opposite/hypotenuse
sin(A) = BC/AC
sin(36) = 13.2/x
x*sin(36) = 13.2
x = 13.2/sin(36)
x = 13.2/0.58778525229248 <<-- make sure calc is in degree mode
x = 22.4571813404936
x = 22.5
This value is approximate (rounded to one decimal place)

----------------------------------------------

Move onto Figure 2

cos(angle) = adjacent/hypotenuse
cos(D) = DE/FD
cos(50) = y/57.4
57.4*cos(50) = y
y = 57.4*cos(50)
y = 57.4*0.64278760968653
y = 36.8960087960069
y = 36.9
This value is approximate (rounded to one decimal place)

----------------------------------------------

Finally, move onto Figure 3

tan(angle) = opposite/adjacent
tan(G) = JH/GH
tan(18) = z/10
10*tan(18) = z
z = 10*tan(18)
z = 10*0.3249196962329
z = 3.249196962329
z = 3.2
This value is approximate (rounded to one decimal place)

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Supplemental Activities - Ch 1
Deffense [45]

x \geq -9; x \leq 6 or in interval notation [-9,6]

To find out what are the steps in solving the below inequality:

Given equation is 2x - 3 > 15

The absolute value function takes any term and transforms it to its non-negative form. Therefore, we must solve the term within the absolute value function for both its negative and positive equivalent.

−15≤2x-3≤15

First, subtract 3  from each segment of the system of equations to isolate the x term while keeping the system balanced:

−15−3≤2x-3−3≤15−3

−18≤2x-6≤12

−18≤2x-6≤12

Now, divide each segment of the system by 2 to solve for x while keeping the system balanced:

-\frac{18}{2}\leq \frac{2x}{2} \leq \frac{12}{2}

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x \geq -9; x \leq 6

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on the horizontal axis.

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Hence the steps to solve an inequality has been show

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