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kherson [118]
2 years ago
9

4, Write an inequality to compare the numbers 7 1/8 v50

Mathematics
1 answer:
Anarel [89]2 years ago
5 0

Answer:

see the explanation

Step-by-step explanation:

we know that

using a calculator

7\frac{1}{8}=7+\frac{1}{8}= 7.125

\sqrt{50}= 7.071

Compare the numbers

Seven an eighth is greater than the square root of fifty.

7\frac{1}{8} > \sqrt{50}  

or

Square root of fifty is less than seven an eighth

\sqrt{50}  

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Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y
Pepsi [2]

Answer:

Option 3 - y=-6x+28

Step-by-step explanation:

Given : Perpendicular to the line x - 6y = 8; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation x - 6y = 8

Converting into slope form y=mx+c,

Where m is the slope.

y=\frac{x-8}{6}

y=\frac{x}{6}-\frac{8}{6}

The slope of the equation is m=\frac{1}{6}

The slope of the perpendicular equation is m_1=-\frac{1}{m}

The required slope is m_1=-\frac{1}{\frac{1}{6}}

m_1=-6

The required equation is y=-6x+c

Substitute point (x,y)=(4,4)

4=-6(4)+c

4=-24+c

c=28

Substitute back in equation,

y=-6x+28

Therefore, The required equation for the line is y=-6x+28

So, Option 3 is correct.

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3 years ago
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