Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:




Solving (b): Probability that none are defective.
The probability that a selection is not defective is:

For two selections, the probability that all are not defective is:




You forgot to expand and simplify it... you only did step one, carry on your doing great 4 marks doesn’t come easy :)
Answer: 70
Step-by-step explanation:
easy
Answer:
13. -4 14. -11 15. 
Step-by-step explanation:
13. (1-3-10)/3
14. (-15+4-22)/3
15. (-7.5+3-6.5)/3
Answer:
<h3>
f[g(x)] = 4x²+6x-3</h3>
Step-by-step explanation:
- f[g(x)]=(2x)²+3(2x)-3...substitute the values of g(x) into the function f(x)
- f[g(x)]=4x²+6x-3...simplified