In the first bag, picking a black marble would be impossible.
The second bag would be likely.
The third bag would be unlikely.
hope this helps!
Double angle formulae involve trigonometric functions of double angles and in order to get its value you must consider the following:
-derive the double angle formula from additional formula
-write the formula for the angle in alternative form
-use the formula to write trigonometric expressions in different forms
-use the formula in the solution of trigonometric equations
And the answer would be 4sin(theta)cos(theta)cos(2theta)
Answer:
a= -6
Step-by-step explanation:
Please see attached picture for full solution.
I skipped a few steps while rewriting the equation into the form of y=mx+c
Here's the step-by-step working if you don't understand:
2x -3y= 6
2x= 3y +6 (+3y on both sides)
2x -6= 3y (-6 on both sides)
3y= 2x -6
<em>y= 2/3x -2</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>(÷3 throughout)
Answer:
(A)
(D)
Step-by-step explanation:
We want to determine which of the expression is equivalent to:
![\sqrt[3]{128}^ x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B128%7D%5E%20x)
By the law of indices:
![\sqrt[3]{128}=128^{1/3}\\$Therefore:\\\sqrt[3]{128}^ x \\=(128^{1/3})^x\\=128^{x/3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B128%7D%3D128%5E%7B1%2F3%7D%5C%5C%24Therefore%3A%5C%5C%5Csqrt%5B3%5D%7B128%7D%5E%20x%20%5C%5C%3D%28128%5E%7B1%2F3%7D%29%5Ex%5C%5C%3D128%5E%7Bx%2F3%7D)
Similarly:
![\sqrt[3]{128}^ x \\=\sqrt[3]{64*2}^ x\\=(4\sqrt[3]{2})^ x\\=(4(2^{1/3}))^x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B128%7D%5E%20x%20%5C%5C%3D%5Csqrt%5B3%5D%7B64%2A2%7D%5E%20x%5C%5C%3D%284%5Csqrt%5B3%5D%7B2%7D%29%5E%20x%5C%5C%3D%284%282%5E%7B1%2F3%7D%29%29%5Ex)