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Degger [83]
3 years ago
14

The Palace of Peace and Accord in Astana, Kazakhstan, was built in 200620062006. The building has a square right pyramid structu

re. The length of a side of the square base is 62\,\text{m}62m62, start text, m, end text, and the vertical height of the pyramid is also 62\,\text{m}62m62, start text, m, end text.
What is the height, hhh, of one of the triangular faces?

Round your answer to the nearest tenth.
Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer: h= 69.3m

Step-by-step explanation:

The correct values in the question are:

year : 2006, length 62, vertical height 62.

So, the measure asked is called slant height . we have to apply the formula:

sh = √(vh^2 + [L/2]^2)

Where:  

vh= vertical height

L= length of a side of the square base

Replacing with the values given:

sh= √(62^2 + [62/2]^2)

sh = √(3,844 + 31^2)

sh= √(3,844 + 961)

sh = √4,805

hs= 69.31 =69.3 m (nearest tenth)

Since in the question that height is called h, h= 69.3

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Jlenok [28]
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For the line with points (0, 0) and (1, 8), the equation is given by:

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\left|\begin{array}{cc} \frac{\partial x}{\partial u} &\frac{\partial x}{\partial v}\\\frac{\partial y}{\partial u}&\frac{\partial y}{\partial v}\end{array}\right| = \left|\begin{array}{cc} 8 &1\\1&8\end{array}\right| \\  \\ =64-1=63

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Answer:

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Step-by-step explanation:

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