Answer:
The fourth answer choice is the correct one: 2(x - 3)
Step-by-step explanation:
2x²-18x+36/x-6 should be factored, as follows:
2(x²-9x+18) / (x-6) = 2(x - 3) (x - 6) / (x - 6)
Substituting x = 6 would result in division by zero and is thus not allowed.
Remembering this, we can reduce 2(x - 3) (x - 6) / (x - 6) to 2(x - 3) for x≠6.
It is asking you to find the sum of k^2 - 1 from k=1 to k=4. Since that is only 4 numbers, calculating the sum by hand wouldn’t be that bad.
(1^2 - 1) + (2^2 - 1) + (3^2 - 1) + (4^2 - 1) = 26
The easier way to find the sum is to use a few simple formulas.
When we have a term that is just a constant c, the formula is c*n.
When we have a variable k, the formula is k*n*(n+1)/2.
When we have a squared variable, the formula is k*n*(n+1)*(2n+1)/6.
In this case, we have a squared variable k^2 and a constant of -1.
So plug in n=4 to the formulas:
4*5*9/6 - 1*4 = 26
The answer is 26
For a number to be rational by definition, a fractional representation of the number must exist.
So N = n/m is rational if n and m are integers.
Since it's given in fractional form it's rational by definition.
Hence false.
Given:
The equation for the area of the first option is:
Where x is the side length of the current square park.
To find:
The side length of the current square park.
Solution:
We have,
It can be written as:
Splitting the middle term, we get
We know that the side length of a park cannot be negative. So, the only possible value of x is 320.
Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.
Answer:
C
Step-by-step explanation:
In the pattern, there are some similarities with the first three circles.
1. The number is on the blue half.
2. The halves switch spots, red-blue, blue-red, red-blue.
So, the next one should have the number on the blue half and the next pattern should be red-blue, blue-red, red-blue, and blue-red.
Which one has both the number on the blue half and the pattern blue-red?
C
Hoped this helped.
