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pogonyaev
3 years ago
15

Please I really need help:

Mathematics
2 answers:
Kobotan [32]3 years ago
6 0
Hi there

The answer is
b.) y=8,000(1.14)^x

Good luck!
docker41 [41]3 years ago
3 0

Answer:

The correct option is B.

Step-by-step explanation:

It is given that price of car is $8000.

Credit limit is $12000.

The monthly interest rate is 14%.

The exponential growth function is defined as

f(x)=a(1+r)^x

Where, a is initial value, r is rate of interest per month and x is time in months.

Here the initial amount of loan is $8000 and monthly interest rate is 0.14.

y=8000(1+0.14)^x

y=8000(1.14)^x

The exponential equation to determine how much you will owe (represented by y) after x months with no more purchases or payments is y=8000(1.14)^x

Therefore the correct option is B.

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WILL MARK BRAINLIEST!
Slav-nsk [51]

Answer:

Second one and the fourth one.

Step-by-step explanation:

Let’s look at this. When we are finding the area of the rectangle, we multiply the length times the width. Let’s look at the first option.

2 times (x + 7)

2x + 14

this one won’t work.

second one:

14(x + 3)

14x + 42

this works.

thrid one.

14(x+5)

14x + 70

nope.

fourth one.

7(2x+6)

14x + 42

works.

fifth one,

2(7x +20)

14x + 40

Does not work.

4 0
3 years ago
Read 2 more answers
A home file is the place where you should keep financial records that you may need to access regularly? True or False
alex41 [277]
True! we have an excel file called moneydoc.xls
6 0
3 years ago
Read 2 more answers
A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int
Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}

By expanding the previous equation:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0

Since there is no accumulation within the tank, expression is simplified to this:

c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}, where c(0) = 0 \frac{pounds}{gallon}.

\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}

The solution of this equation is:

c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})

The salt concentration after 8 minutes is:

c(8) = 0.166 \frac{pounds}{gallon}

The instantaneous amount of salt in the tank is:

m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds

3 0
3 years ago
kelly made one batchof peanut and pretzal snack mix. how many grams does she need to add to the snack mix to make 2 kilograms
Dominik [7]
2000g
1000g=1kg
Hence 2000g =2kg
Kelly needs to add 2000g to the snack mix to make 2kg.
3 0
3 years ago
What is the expression for the volume of the cylinder?
gulaghasi [49]

9xπ ft³

The volume (V) of a cylinder is calculated using the formula

V = area of base × height

The volume of the oblique cylinder is the same as the volume of the right cylinder

Tilting the cylinder over does not change the volume, imagine tilting a tin of beans, the volume is unchanged

V = 9xπ ft³


6 0
4 years ago
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