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lora16 [44]
3 years ago
7

Consider a drive that states: LBA = 976,562,500. Demonstrate, in writing, how you would calculate the total capacity of this dri

ve both as defined by hard drive manufacturers and by computer science. Assume a sector size of 512 bytes.
Computers and Technology
1 answer:
yarga [219]3 years ago
7 0

I guess the correct answer is 465.66 GB

Solution,

1024x1024x1024 = 1073741824 Bytes per gigabyte

976562500x512 = 500,000,000,000

500,000,000,000/1073741824 = 465.66 GB

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Why are new versions of applications packages released often ​
stellarik [79]

Answer:

The answer is "new version of application provides more easy to use".

Explanation:

  • In computer science, an application is a program, that is installed on the computer. There are many types of application software, that are "gaming software, working software, programming software, etc." At the end of time users want some new things in software to know users need programmer developed new versions of the software.
  • The update usually improves the device or service in its current version, whilst an improvement is an entirely new version. Installation is usually free and easy. You also have to wait for updates that are difficult to install.
5 0
3 years ago
Que significa el término “Informática”?
Ad libitum [116K]

Answer:

Explanation:

proviene del francés informatique, implementado por el ingeniero Philippe Dreyfus a comienzos de la década del '60. ... De esta forma, la informática se refiere al procesamiento automático de información mediante dispositivos electrónicos y sistemas computacionales.

4 0
3 years ago
QUESTION
Lady_Fox [76]

Answer:

Explanation:

#include <iostream>

using namespace std;

int main ()

{

   int responses[30],count[6];

   int score = 0;

   string resp = " ";

   for (int i = 0; i < 30; i++)

   {

    responses[i] = 0;

   }

   for (int i = 0; i < 6; i++)

   {

    count[i,1]=0;

    count[i,2]=0;

    count[i,0]=0;

   }

   while ((resp != "Y") && (resp != "y"))

   {

    for (int i = 0; i < 30; i++)

    {

        while ((score > 5) || (score < 1))

           {

            cout << "Student " << (i+1)<< " please enter a value (1-5):";

            cin >> score;

        }

           responses[i] = score;

           if((score > 5)||(score<1))

           {

               if(score==1) count[1]++;        

               if(score==2) count[2]++;        

               if(score==3) count[3]++;        

               if(score==4) count[4]++;        

               if(score==5) count[5]++;        

           }

           score = 0;

    }

    cout<< "Response               Frequency              Percentage"<<endl;;

    cout<< "    1                      "<<count[1]<<"               "<<(count[1]/30)<<"%"<<endl;

    cout<< "    2                      "<<count[2]<<"               "<<(count[2]/30)<<"%"<<endl;

    cout<< "    3                      "<<count[3]<<"               "<<(count[3]/30)<<"%"<<endl;

    cout<< "    4                      "<<count[4]<<"               "<<(count[4]/30)<<"%"<<endl;

    cout<< "    5                      "<<count[5]<<"               "<<(count[5]/30)<<"%"<<endl;

    cout<< "Do you want to exit? Press Y to exit any other key to continue: ";

    cin>> resp;

   }

   return 0;

}

8 0
3 years ago
Which of the following is the MOST important consideration when planning your budget?
nata0808 [166]
<span>Budget for fixed expenses before flexible expenses.</span>
5 0
4 years ago
Read 2 more answers
100 POINTS FOR ANYONE WHO CAN DO THIS!
Nataly [62]

Let's check what can be modified

Before calling def we need adjective and conjunctions stored inside variables

Store them(You may change according to your choice)

\tt adjectives=("foolish","bad","long","hard")

\tt conjunctions=("and","but","for","after")

We have to make optional ,easy way ask the user to do instead of yourself .

\tt con=input("Enter\: yes\: if \:you \:want \:to \:use \:conjunctions:")

\tt adj=input("Enter\:yes\:if\:you\:want\:to\:use\: adjectives:")

If they click then we can proceed else no problem let the program run

\tt def\: conjunctionPhrase():

\quad\tt if\: con=="yes":

\quad\quad\tt return\:random.choice(conjunctions)+"\:"+nounPhrase()

\quad\tt else:

\quad\quad\tt continue

  • You may use pass also

\tt def\: adjectivePhrase():

\quad\tt if\:adj=="yes":

\quad\quad\tt return\:random.choice(adjectives)+"\:"+nounPhrase()

\quad\tt else:

\quad\quad\tt continue

4 0
2 years ago
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