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11111nata11111 [884]
1 year ago
6

A. In I/O interation between OS and devices, describe how hybrid mechanism works?

Computers and Technology
1 answer:
enyata [817]1 year ago
4 0

a. I/O Hardware. Devices communicate with the computer via signals sent over wires or through the air. Devices connect with the computer via ports, e.g. a serial or parallel port. A common set of wires connecting multiple devices is termed a bus.

b. The main difference between interrupt and polling is that in interrupt, the device notifies the CPU that it requires attention while, in polling, the CPU continuously checks the status of the devices to find whether they require attention. In brief, an interrupt is asynchronous whereas polling is synchronous.

c. flash memory

A solid-state drive (SSD) is a solid-state storage device that uses integrated circuit assemblies to store data persistently, typically using flash memory, and functioning as secondary storage in the hierarchy of computer storage.

#◌⑅⃝●♡⋆♡Nåmřāthā ♡⋆♡●⑅◌

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Name the major types of computer systems from slowest to fastest. ​
Vadim26 [7]

Answer:

Cache is the fastest and most expensive, RAM is slower and less expensive, and virtual memory is the slowest and least expensive type.

Explanation:

3 0
2 years ago
SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R
Ne4ueva [31]

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.*;

class UserName{

  ArrayList<String> possibleNames;

  UserName(String firstName, String lastName){

      if(this.isValidName(firstName) && this.isValidName(lastName)){

          possibleNames = new ArrayList<String>();

          for(int i=1;i<firstName.length()+1;i++){

              possibleNames.add(lastName+firstName.substring(0,i));

          }  

      }else{

          System.out.println("firstName and lastName must contain letters only.");

      }

  }

  public boolean isUsed(String name, String[] arr){

      for(int i=0;i<arr.length;i++){

          if(name.equals(arr[i]))

              return true;

      }

      return false;

  }

  public void setAvailableUserNames(String[] usedNames){

      String[] names = new String[this.possibleNames.size()];

      names = this.possibleNames.toArray(names);

      for(int i=0;i<usedNames.length;i++){

          if(isUsed(usedNames[i],names)){

              int index = this.possibleNames.indexOf(usedNames[i]);

              this.possibleNames.remove(index);

              names = new String[this.possibleNames.size()];

              names = this.possibleNames.toArray(names);

          }

      }

  }

  public boolean isValidName(String str){

      if(str.length()==0) return false;

      for(int i=0;i<str.length();i++){

          if(str.charAt(i)<'a'||str.charAt(i)>'z' && (str.charAt(i)<'A' || str.charAt(i)>'Z'))

              return false;

      }

      return true;

  }

  public static void main(String[] args) {

      UserName person1 = new UserName("john","smith");

      System.out.println(person1.possibleNames);

      String[] used = {"harta","hartm","harty"};

      UserName person2 = new UserName("mary","hart");

      System.out.println("possibleNames before removing: "+person2.possibleNames);

      person2.setAvailableUserNames(used);

      System.out.println("possibleNames after removing: "+person2.possibleNames);

  }

}

Kindly check the attached image below for the code output.

5 0
3 years ago
IF YOU GET 5/5 RIGHT YOU WILL GET BRAINLIEST AND 50 [POINTS
natta225 [31]

Answer:

The sort function

Explanation:

Because it will sort all the numbers.

4 0
2 years ago
Read 2 more answers
How do I convert a number into a percentage in excel
Annette [7]

format>number>percent

Explanation:

You click the box you want to convert into a percentage and then at the top where it says file, edit, view, insert, format, data, tools, add-ons and help, click format then number and then percent. This should convert your number into a percentage.

8 0
3 years ago
A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,
Svetllana [295]

Answer:

0.8488

Explanation:

Let E =error found by test 1

Let F=error found by test 2

Let G=error found by test 3

Let H=error found by test 4

Let I= error found by test 5

Given P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

therefore P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Tests are independent P(not E & not F &not G & not H & not I=P(notE)*P(notF)*P(notG)*P (notH)*P (not I) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(found by at least one test)= 1- P(not found by any test)=1-P(not E& not F & not G & not H & not I ) = 1-0.1512 = 0.8488

5 0
3 years ago
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