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irakobra [83]
3 years ago
14

PLEASE HELP

Mathematics
1 answer:
larisa [96]3 years ago
5 0

Answer:

1.) not safe

2.)

18 \sqrt{3}

Step-by-step explanation:

1.) given the length of the ladder = 15ft.

and the height to the top of ladder when leaned against a wall is 14.8ft. This all forms a right triangle.

with what we are given we can solve for the angle it creates from the ground to the leaned ladder by using the SOHCAGTOA. Whike we do this keep in mind its not safe for a ladder to create an angle more than 70 degrees.

in this case if we are solving for the angle where the height is opposite we will use SOH. because we know the oposite and the hyp. Sin(theta) = opp/hyp

\sin(theta) =  \frac{14.8}{15}

sin^{ - 1}  ( \frac{14.8}{15} ) = 81 \: degrees

therefore not safe.

2.)

your givin 90 and 60. remember all interior angles add up to 180.

therefore 30 would be the unknown angle.

knowing that we use the <u>chart</u> at the top.

across from 30 is 6. so we put that by x. (remember we are doing this to find the height for our area of a triangle formula = base time height devide by 2.)

we need to find the height so since we kmow what x is we know what is across from 60 which is

6 \sqrt{3}

so we plug that into our formula for area of triangle and u should get 18

\sqrt{3}

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PLease answer !!! Find constants $A$ and $B$ such that \[\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}\] for all
Xelga [282]

Answer:

1. (A,B) = (3,-2)

2. The values of t are: -3, -1

Step-by-step explanation:

Given

\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}

|t| = 2t + 3

Required

Solve for the unknown

Solving \frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}

Take LCM

\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{(x - 2)(x-1)}

Expand the denominator

\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - 2x + x -2}

\frac{x + 7}{x^2 - x - 2} = \frac{A(x+1) + B(x-2)}{x^2 - x -2}

Both denominators are equal; So, they can cancel out

x + 7 = A(x+1) + B(x-2)

Expand the expression on the right hand side

x + 7 = Ax + A + Bx - 2B

Collect and Group Like Terms

x + 7 = (Ax + Bx)  + (A - 2B)

x + 7 = (A + B)x + (A - 2B)

By Direct comparison of the left hand side with the right hand side

(A + B)x = x

A - 2B = 7

Divide both sides by x in (A + B)x = x

A + B = 1

Make A the subject of formula

A = 1 - B

Substitute 1 - B for A in A - 2B = 7

1 - B - 2B = 7

1 - 3B = 7

Subtract 1 from both sides

1 - 1 - 3B = 7 - 1

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Divide both sides by -3

B = -2

Substitute -2 for B in A = 1 - B

A = 1 - (-2)

A = 1 + 2

A = 3

Hence;

(A,B) = (3,-2)

Solving |t| = 2t + 3

Because we're dealing with an absolute function; the possible expressions that can be derived from the above expression are;

t = 2t + 3    and   -t = 2t + 3

Solving t = 2t + 3

Make t the subject of formula

t - 2t = 3

-t = 3

Multiply both sides by -1

t = -3

Solving -t = 2t + 3

Make t the subject of formula

-t - 2t = 3

-3t = 3

Divide both sides by -3

t = -1

<em>Hence, the values of t are: -3, -1</em>

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Answer: 28.26


Step-by-step explanation:

What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²

You are given the diameter in these problems, so you need radius.

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