Exact Form:
x
=
0
,
−
9
√
3
9
√
2
x
=
0
,
-
3
9
2
9
Decimal Form:
x
=
0
,
−
1.04608191
…
x
=
0
,
-
1.04608191
…
Answer:
B. equivalent
Step-by-step explanation:
Our two equations are:
![y=-\frac{1}{3} x +\frac{2}{3}](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B3%7D%20x%20%2B%5Cfrac%7B2%7D%7B3%7D)
![2x+6y=4](https://tex.z-dn.net/?f=2x%2B6y%3D4)
Let's use substitution and plug in the expression
for y in the second equation. That way, we're getting rid of a variable so we can solve for the other:
![2x+6y=4](https://tex.z-dn.net/?f=2x%2B6y%3D4)
![2x+6(-\frac{1}{3} x +\frac{2}{3})=4](https://tex.z-dn.net/?f=2x%2B6%28-%5Cfrac%7B1%7D%7B3%7D%20x%20%2B%5Cfrac%7B2%7D%7B3%7D%29%3D4)
![2x-2x+4=4](https://tex.z-dn.net/?f=2x-2x%2B4%3D4)
![4=4](https://tex.z-dn.net/?f=4%3D4)
![0=0](https://tex.z-dn.net/?f=0%3D0)
This means that there are an infinite number of solutions possible for this system - any x value will work. So, the answer is equivalent, because these two equations are essentially the same.
Answer:
The answer for the code is CGIA
Step-by-step explanation:
Answer:
20 socks fit $14.99 is the best deal out of the 3
Step-by-step explanation:
Here, we want to know the bag that contain the best deals for socks .
The best way to go about this is to know the unit prices of socks in each of the bags.
Let’s proceed;
12 socks for $9.99
The unit price here is 9.99/12 = 0.8325 per socks
20 socks for 14.99
Unit price here is 14.99/20 = 0.7495
10 socks for 19.99
The unit price here is 19.99/10 = 1.999
Out of all these options , we can see that the second option is actually the cheapest and offers what we should be pick as we are looking for suppliers since it charges the lowest;
So the best deal for socks is in the bag of 20 socks for $19.99
Answer:
and
![\frac{15}{10} -\frac{12}{10} = \frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B10%7D%20-%5Cfrac%7B12%7D%7B10%7D%20%3D%20%5Cfrac%7B3%7D%7B10%7D)
Step-by-step explanation:
Given
![\frac{3}{2} - \frac{6}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%20-%20%5Cfrac%7B6%7D%7B5%7D)
Now the L.C.M = 10
= ![\frac{15-12}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B15-12%7D%7B10%7D)
= ![\frac{15}{10} -\frac{12}{10} = \frac{3}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B10%7D%20-%5Cfrac%7B12%7D%7B10%7D%20%3D%20%5Cfrac%7B3%7D%7B10%7D)