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NARA [144]
3 years ago
5

Ernesto baked 3 cakes in 2 1/2 hours. Assume that the number of cakes baked varies directly with the number of hours. Write and

solve a direct variation equation to find how many cakes can be baked in 7 1/2 hours.
Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0

We know that in 2 ½ hours (2.5 hours), we can create 3 cakes hence:

C = k t

where C is number of cakes, k is constant, and t is time

k = 3 cakes / (2.5 hours)

k = 1.2

C = 1.2 t

 

So for t = 7 ½ hours = 7.5 hours

C = 1.2 (7.5)

<span>C = 9 cakes in 7 ½ hours</span>

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Answer:

\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}

Step-by-step explanation:

We have:

\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}

For sine use:

\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x

Substitute:

\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}

θ in IV quadrant, therefore sine is negative.

\sin\theta=-\dfrac{\sqrt2}{2}

For tangent use:

\tan x=\dfrac{\sin x}{\cos x}

Substitute:

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8 0
3 years ago
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Step-by-step explanation:

We have, Sorin hits a cricket ball straight up into the air. After 1.5 s, the ball is falling straight down with a speed of 6.5 m/s.

We want to find the initial vertical velocity of the ball.

The relation between initial speed, final speed, acceleration and time is given by using first equation of kinematics. Let v₀ is the initial speed. So,

v=v_o +at

Here, v = -6.5 m/s, t = 1.5 s and a = -g

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So, the initial velocity of the ball is 8.2 m/s and the formula used is (1).

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