Show all work please will give brainliest answer❕❗️❕❗️❕❗️❕❗️❕David drops a ball from a bridge at an initial height of 100 meters
. (a) What is the height of the ball to the nearest tenth of a meter exactly 3 seconds after he releases the ball? (b) How many seconds after the ball is released will it hit the ground?
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is: delta x= (v)(t) -0.5(acceleration)(time)^2 delta x= 29.4 times (3) - 0.5 (9.8) times 9 delta x= 44.1 100 minus 44.1 equals 55.9, which is the answer for part a.
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PART B: The kinematic equation for this is: delta x= (initial velocity) times time plus 0.5 (a)(time)^2 100=(0)times(x) plus 0.5 (a)(time)^2 100=0.5(9.8)(x)^2 100=4.9x^2 100/4.9 is approxamitely 20.4. The squareroot of this is approxamitely 4.5. 4.5 seconds
The solutions to system of equations are the point of intersection of the graphs of the equations. The point of intersection of the graphs of the given equation is (0, 2). Therefore, point (1, 1) is not a solution to the system of equation.
The 2 numbers cannot be positive but the 2 numbers can be both positive and negative like: 2+(-3)= -1. Both numbers can also be negative like: (-3)-(-2)=-1.
