Width =3.5, length = 4
Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl
Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w
0 = 2w^2 - 3w - 14
which factors into
(2w - 7) (w + 2)
Solving for w
2w - 7 = 0
2w = 7
w = 3.5
w+2 = 0
w = -2
So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5
Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14
So the width is 3.5 and the length is 4.
Answer:
(2,6) and (-2,6) is in the second box
(8,-2) and (8,2) is in the first box
(-5,7) and (-5,-7) is in the first box
(-3,-3) and (3,-3) is in the second box
Plug 8 for y
8 = 2x + 4
Subtract 4
4 = 2x
Divide by 2
x = 2
Plug 16 for y
16 = 2x + 4
Subtract by 4
12 = 2x
Divide by 2
x = 6
Substitute 20 for y
20 = 2x + 4
16 = 2x
x = 8
Substitute 22 for y
22 = 2x + 4
18 = 2x
9 = x
So the values are 2, 6, 8, 9
Answer:
The answer is C
Step-by-step explanation:
(I'm not completely sure)
2,14 4,16 6,18 8,20 f=s+12
