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KengaRu [80]
3 years ago
5

If the area of the rectangle shown is 150 square feet, we can use the equation 2x2 - 5x = 150 to find its dimensions. If the sol

ution to the equation is x = 10, what are the dimensions of the rectangle?
Mathematics
2 answers:
Serjik [45]3 years ago
7 0
X=-150 or X=-146/5 I think.
natita [175]3 years ago
7 0

Answer:

10ft×15ft

Step-by-step explanation:

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The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an
yan [13]

Answer:

The length of the side of an equilateral traingle s=2\sqrt{2} inches

Step-by-step explanation:

Given that the area of an equilateral triangle is given by

A=3^\frac{1}{2}s^2

It can be written as

a=\frac{\sqrt{3}}{4} s^2 Square inches        (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is 12^\frac{1}{2} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches

It can be written as

A=12^\frac{1}{2}

A=\sqrt{12} square inches           (2)

Now comparing equations (1) and (2) we get

\frac{\sqrt{3}}{4}s^2=\sqrt{12}

\frac{\sqrt{3}}{4}s^2=\sqrt{4\times 3}

Dividing by \frac{\sqrt{3}}{4} on both sides we get

\frac{\frac{\sqrt{3}}{4}s^2}{\frac{\sqrt{3}}{4}}=\frac{2\sqrt{3}}{\frac{\sqrt{3}}{4}}

\frac{\sqrt{3}}{4}s^2\times\frac{4}{\sqrt{3}}=2\sqrt{3}\times\frac{4}{\sqrt{3}}

s^2=8

s=\sqrt{8}

Therefore s=2\sqrt{2} inches

Therefore the length of the side of an equilateral traingle s=2\sqrt{2} inches

3 0
3 years ago
Una de las piezas de un monumento tiene forma crónica du altura es de 9cm y el area de su base de 10cm, su volumen es de?
Sergio [31]

Answer:

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Step-by-step explanation:

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Can you go deeper into the question?

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3 years ago
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