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Dafna11 [192]
3 years ago
7

Find and interpret the slope and y-intercept of y=40x+30

Mathematics
1 answer:
rjkz [21]3 years ago
3 0
The slope is 40 and the y-intercept is 30. Umm... What exactly are you asking for? I'm a bit confused about this question.
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During scuba lessons, Sue dove 30 feet, Harriet dove 120 feet, and Kathy dove 90 feet.What integers represent these depths? Orde
aleksley [76]
120, 90, 30 if you're going from the depths of the water to water level
3 0
3 years ago
Find the x-intercepts of the parabola with vertex (1,1) and y-intercept (0,-3). Write your answer in this form (x of 1 , y of 1)
Vikki [24]
Remember that the vertex form of a parabola or quadratic equation is:

y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola  (and a is half the acceleration of the of the function, but that is maybe too much :P)

In this case we are given that the vertex is (1,1) so we have:

y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:

-3=a(0-1)^2+1

-3=a+1

-4=a so our complete equation in vertex form is:

y=-4(x-1)^2+1

Now you wish to know where the x-intercepts are.  x-intercepts are when the graph touches the x-axis, ie, when y=0 so

0=-4(x-1)^2+1  add 4(x-1)^2 to both sides

4(x-1)^2=1  divide both sides by 4

(x-1)^2=1/4  take the square root of both sides

x-1=±√(1/4)  which is equal to

x-1=±1/2  add 1 to both sides

x=1±1/2

So x=0.5 and 1.5, thus the x-intercept points are:

(0.5, 0) and (1.5, 0)  or if you like fractions:

(1/2, 0) and (3/2, 0) :P
4 0
3 years ago
Which pair of funtions is not a pair of inverse functions? please help!!
antiseptic1488 [7]

Answer:

f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> f(x)=\frac{x+1}{6} , g(x)=6x-1

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y+1}{6}

Isolate the variable y

6x=y+1

y=6x-1

Let

f^{-1}(x)=y

f^{-1}(x)=6x-1

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> f(x)=\frac{x-4}{19} , g(x)=19x+4

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y-4}{19}

Isolate the variable y

19x=y-4

y=19x+4

Let

f^{-1}(x)=y

f^{-1}(x)=19x+4

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> f(x)=x^{5}, g(x)=\sqrt[5]{x}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=y^{5}

Isolate the variable y

fifth root both members

y=\sqrt[5]{x}

Let

f^{-1}(x)=y

f^{-1}(x)=\sqrt[5]{x}

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

x=\frac{y}{y+20}

Isolate the variable y

x(y+20)=y

xy+20x=y

y-xy=20x

y(1-x)=20x

y=20x/(1-x)

Let

f^{-1}(x)=y

f^{-1}(x)=20x/(1-x)

\frac{20x}{1-x}\neq \frac{20x}{x-1}

therefore

f(x) and g(x) is not a pair of inverse functions

7 0
3 years ago
Read 2 more answers
I don't know how to work it out. show work pls
mel-nik [20]
1g is equal to 0.001kg

678g = 0.678kg

(678 x 0.001 = 0.678)
7 0
3 years ago
If your weekly allowance of $20 increases by 10%, then decreases by 10%, how much will you earn each week?
Alika [10]

1)  The amount M 1 IS $20 increases by 10% = 10 % *(20) + 20 = 22

2) The amount M1 decreases by 10% = 22- (10%*22) = $ 19,8 IS THE AMOUNT that i earn each week

7 0
3 years ago
Read 2 more answers
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