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lord [1]
2 years ago
15

Which equation is in slop-intercept form?

Mathematics
2 answers:
Goshia [24]2 years ago
7 0

Answer:

\boxed {\boxed {\sf y=3x+12}}

Step-by-step explanation:

The slope-intercept form of an equation is:

y=mx+b

where <em>m </em>is the slope and <em>b</em> is the y-intercept.

Let's evaluate each answer choice. The one in slope-intercept form will have the y variable isolated on one side of the equation.

  • A. 2x+3y=21: This is <em>not</em> is slope-intercept form. The y is not isolated.
  • B. y-7=3(x+4): Again, this isn't slope-intercept form. A 7 is being subtracted from y
  • C. y²=3x²-6: This also isn't correct. y is being squared.
  • D. y=3x+12: This choice is correct. The y is all alone on the left side of the equation.

The equation in slope-intercept form is <u>D. y=3x+12</u>

frosja888 [35]2 years ago
6 0

Step-by-step explanation:

Only D, y = 3x + 12 is in slope-intercept form.

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A line contains the point (4, 2) and has a slope of −3.
Naya [18.7K]

Answer: the equation is y = - 3x + 14

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

c represents the y intercept

m represents the slope of the straight line.

The slope of the given line is - 3 and it contains the point (4, 2)

To determine the y intercept, we would substitute m = - 3, x = 4 and

y = 2 into y = mx + c. It becomes

2 = - 3 × 4 + c

2 = - 12 + c

c = 12 + 2

c = 14

The equation becomes

y = - 3x + 14

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The radius of the circle whose equation is (x-3)^2 + (y+1)^2 = 16 is
Firdavs [7]

Answer:

4

Step-by-step explanation:

The general equation of a circle with center (a, b) and radius r is given by the equation;

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We have been given the following equation;

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Comparing this with the general equation above;

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