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Nitella [24]
4 years ago
7

one day, gale and hector each recorded temperatures outside their homes. function g shows tempatures, in F, gale recorded c hour

s after noon. the graph shows temperatures, in f, hector recordrf x hours after noon

Mathematics
2 answers:
myrzilka [38]4 years ago
8 0
Hector, 4 degrees, Gale
DedPeter [7]4 years ago
6 0

Answer:

1. Hector's

2. 4^{o} F

3. Gale's      

Step-by-step explanation:

We have been given a graph and table of data about recorded temperatures outside Gale and Hector's homes.    

We can see from graph that at noon temperature outside Hector's home is 3 degree Fahrenheit that is h(0). Our table shows the temperature outside Gale's home at noon is -1 degree Fahrenheit that is g(0).            

Let us find the difference between temperatures outside Gale and hectors home at noon.

\text{ Difference of temperatures}=3--1=3+1=4          

We can see that at noon temperature outside Hector's home is 4 degree Fahrenheit more than temperature outside Gale's home.    

Therefore, at noon, temperature outside of Hector's home was 4^{o} F warmer than temperature outside of Gale's home.    

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almond37 [142]

Answer:

Her pay for the week= $ 611.325

Step-by-step explanation:

Sallie is paid $ 11.40 per hour for regular hours.

The total regular hours worked during the week are

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She works overtime during the week

Monday + Tuesday + Wednesday = 2+ 1/4+  1 1/2=  2+ 1/4 + 3/2

= 8 +1+ 6/4=15/4 = 3 3/4 hours

Over the weekend she works five hours .

So the total pay would be

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3 0
3 years ago
HELP PLEASE<br>solve for x : 2.1x - 3.6 = 8<br>1) 6.77<br>2)2.1<br>3)1.22<br>4)5.52<br>​
ss7ja [257]

Answer:

Rounding x = 5.52

Step-by-step explanation:

2.1x - 3.6 = 8

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2.1x = 11.6

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2.1x/2.1 = 11.6/2.1

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3 0
3 years ago
PLEASE ANSWER + BRAINLIEST!!
Drupady [299]
To solve this problem you must apply the proccedure shown below:
 1. You have the followin quadratic equation given in the problem above: <span>x^2+3x+1
 2. Therefore, you have:
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 x^2+3x+9/4=-1+9/4
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