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3 years ago

The area of the entire figure is 1 square unit

Mathematics

1 answer:

Anton [14]3 years ago

4 0

Answer:

Area of shaded part = 0.42 unit²

Step-by-step explanation:

Given:

Length of shaded part = 0.7 unit

Width of shaded part = 3 x 2 = 0.6 unit

Find:

Area of shaded part

Computation:

Area of rectangle = L x B

Area of shaded part = 0.7 x 0.6

Area of shaded part = 0.42 unit²

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Endpoint given the Midpoint: * The midpoint of RP is M(2, 4). If one of the end points is R(-1,7), find the coordinates of the o

marin [14]

Answer:

The coordinates of other point are: (5,1)

Step-by-step explanation:

Given coordinates are:

M(x,y) = (2,4)

R(x_1,x_2) = (-1,7)

We have to find the coordinates of other point (x2,y2)

The formula for mid-point is given by:

$M(x,y) = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Putting the values we get

$(2,4) = (\frac{-1+x_2}{2}, \frac{7+y_2}{2})$

Putting respective elements equal

$\frac{-1+x_2}{2} = 2\\-1+x_2 = 2*2\\-1+x_2 = 4\\x_2 = 4+1\\x_2 = 5\\And\\\frac{7+y_2}{2} = 4\\7+y_2 = 4*2\\7+y_2 = 8\\y_2 = 8-7\\y_2 = 1$

Hence,

The coordinates of other point are: (5,1)

8 0

3 years ago

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

Can you help me with this question?

Rufina [12.5K]

Answer:

16.2

Step-by-step explanation:

The angle internal to the triangle at B is the supplement of the one shown, so is 65°. That is equal to the angle internal to the triangle at D. Since the vertical angles at C are congruent, the two triangles are similar by the AA theorem.

Corresponding sides of similar triangles are proportional, so we can write the proportion shown in the attachment:

BC/FC = DC/AC

BC = FC(DC/AC) = 21.6(7.2/9.6)

BC = 16.2 . . . . matches the first choice

4 0

4 years ago

You are making a new type of deodorant from two different mixtures the first mixture is 30% smell proof and the second mixture i

Readme [11.4K]

Answer:

600 L of 30% proof and 400 L of 80% proof is needed

Step-by-step explanation:

Let the amount of 30% smell proof be x while that of 80% smell proof is y

Then;

x + y = 1000 •••••(i)

Also;

30% of x + 80% of y = 50% of 1000

0.3x + 0.8y = 500 •••••(ii)

From i, x = 1000 - y

Put this into ii

0.3(1000-y) + 0.8y = 500

300 - 0.3y + 0.8y = 500

0.5y = 500-300

0.5y = 200

y = 200/0.5

y = 400 L

But x = 1000 - y

x = 1000 - 400 = 600 L

3 0

3 years ago

I need all the angles of all four please, I uploaded them in order of each question

adelina 88 [10]

Answer:

Blurry

Step-by-step explanation:

8 0

3 years ago