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Papessa [141]
4 years ago
10

Find all numbers whose absolute value is 2 .

Mathematics
2 answers:
Alinara [238K]4 years ago
8 0
Are you talking About like what 2 all goes into

Amiraneli [1.4K]4 years ago
6 0
Absolute value of a real number, is the distance between that number and 0 on a number line. Therefore the absolute value of 2 is 2 and negative 2
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3y^4/3y^2-6=10 please help I will.mark it as the brainliest answer!​
Korolek [52]
Y=4 or -4
Explanation: trust me bro
6 0
3 years ago
Read 2 more answers
Drag each tile to the correct box. Determine the type of risk each investment is likely to incur.
leonid [27]
Do you have a picture, I need one to help you, otherwise I can’t.
4 0
3 years ago
Find the coordinates of the center of the following circle.<br><br> (x - 3)² + (y - 7)² = 49
Zepler [3.9K]

When you write the equation of a circle in the form

(x-x_0)^2+(y-y_0)^2=r^2

Then the center of the circle has coordinates (x_0, y_0) and the radius is r

So, in your case, the center of the circle is (3,7)

7 0
4 years ago
Given that (-4,1) is on the graph of f(x), find the corresponding point for the function 4f(x)
AVprozaik [17]
F(-4) = 1
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The point of interest is (-4, 4).
8 0
3 years ago
En una muestra de 50 restaurantes de comida rápida, la venta media fue de $3.000, y la desviación estándar, $200. El intervalo d
Step2247 [10]

Respuesta:

(2945.411; 3054.589)

Explicación paso a paso:

Dado ;

Tamaño de la muestra, n = 50

Media, xbar = 3000

Desviación estándar, s = 200

Nivel de confianza, Zcrítico al 95% = 1,96

El intervalo de confianza se define como:

Xbar ± margen de error

Margen de error = Zcrítico * s / sqrt (n)

Margen de error = 1,96 * 200 / sqrt (50)

Margen de error = 54.589

Límite inferior = (3000 - 54.589) = 2945.411

Límite superior = (3000 + 54.589) = 3054.589

(2945.411; 3054.589)

8 0
3 years ago
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