You can choose to put all the numbers into decimals or fractions.
In this case, I will put the numbers all in decimals.
We already have 2.07, -2.67, and 2.67

in a decimal is 2.7 because 7 is in the 'tenths' place and ten was our denominator
So all of our numbers are 2.7 2.01 2.67 and -2.67
Obviously a negative number will be last and you can line the other numbers to see which is the greatest
2.67
2.70 (if there is nothing there we can always put a zero)
2.01
So the first digit is all 2 so we look at the next digits which are 6, 7, and 0
You should know how to order those numbers, so do the same here.
-2.67, 2.01, 2.67

(we had to change it back to a fraction)
Hope that helped :)
So you already know the difference between the new number and original number, so all you have to do now is plug it in to this: Percentage Change=Difference/Original Number x100. So 17.99/257=.07x100 which equals 7%. So B is the correct answer.
Answer:
C = (1, -1)
Step-by-step explanation:
For that 3:1 division, the calculated value of point B is ...
B = (3C +1A)/(3+1)
Solving for the value of C, we find ...
4B = 3C + A . . . . multiply by 4
4B -A = 3C . . . . . subtract A; next divide by 3.
C = (4B -A)/3 = ((4(-1)-(-7))/3, (4(0)+-3)/3) . . . . substitute given values
C = (3/3, -3/3) . . . . simplify a bit
C = (1, -1)
Answer:
6 teaspoons
Step-by-step explanation:
2 teaspoons = 1/3 tsp of salt
6 teaspoons = 1 tsp of salt
This was done by multiplying 2 by 3 since 3 thirds (3/3) make one whole.
So if 2 teaspoons are used for 1/3 teaspoon of salt, 4 teaspoons would be used for 2/3 teaspoon of salt and 6 teaspoons would be used for 1 teaspoon of salt.
9514 1404 393
Answer:
step 2; misapplication of the distributive property
Step-by-step explanation:
To eliminate parentheses, the distributive property of multiplication over addition tells you the outside factor is applied to each of the terms inside. The second step should be ...
Step 2: (0.5)(4) +(0.5)(1.2x) +(0.5)(-3.1) = 2 +0.6x -1.55
Shane's mistake was that he added the factor to the first term, subtracted the factor from the coefficient of the second term, and added the factor to the third term. He was inconsistent even in his misapplication of the distributive property.