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kiruha [24]
3 years ago
13

-8 - (-15) + 30 equals​

Mathematics
1 answer:
Phantasy [73]3 years ago
8 0

The answer to your problem is 11

You might be interested in
(x^2y+e^x)dx-x^2dy=0
klio [65]

It looks like the differential equation is

\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0

Check for exactness:

\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x

As is, the DE is not exact, so let's try to find an integrating factor <em>µ(x, y)</em> such that

\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0

*is* exact. If this modified DE is exact, then

\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}

We have

\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu

Notice that if we let <em>µ(x, y)</em> = <em>µ(x)</em> be independent of <em>y</em>, then <em>∂µ/∂y</em> = 0 and we can solve for <em>µ</em> :

x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}

The modified DE,

\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0

is now exact:

\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}

So we look for a solution of the form <em>F(x, y)</em> = <em>C</em>. This solution is such that

\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}

Integrate both sides of the first condition with respect to <em>x</em> :

F(x,y) = -e^{-x}y - \dfrac1x + g(y)

Differentiate both sides of this with respect to <em>y</em> :

\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C

Then the general solution to the DE is

F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}

5 0
3 years ago
Is 3/10 greater than 5/10
storchak [24]

3 of anything is almost always less than 5 of the same thing.
That's true for cows, rocks, trees, fish, salt-shakers, and babies.
I can't think of any object where it wouldn't be true.
Why wouldn't it be true for tenths ?

Let me say it another way:

No.  3/10  is <em>less than</em>  5/10 .


3 0
3 years ago
Read 2 more answers
Enter what that means? <br> Help someone.
Luda [366]

\frac{x^2}{3} is the same as \frac{1}{3}x^2

Dividing by 3 is the same as multiplying by the fraction 1/3

7 0
3 years ago
DUDE IVE BEEN ASKIN FOR HELP FOR AWHILE PLEASE HELP I BEG OF U I WILL DO ANYTHING EXTRA POINTS WHATEVER
Mars2501 [29]

Answer:

i can help with a littel bit of it

Step-by-step explanation:

1. answer

29±95‾‾‾√9

x

=

−

2

9

±

95

i

9

=−0.222222+1.08298

x

=

−

0.222222

+

1.08298

i

=−0.222222−1.08298

x

=

−

0.222222

−

1.08298

i

Find the Solution for:

92+4+11=0

9

x

2

+

4

x

+

11

=

0

using the Quadratic Formula where

a = 9, b = 4, and c = 11

=−±2−4‾‾‾‾‾‾‾‾√2

x

=

−

b

±

b

2

−

4

a

c

2

a

=−4±42−4(9)(11)‾‾‾‾‾‾‾‾‾‾‾‾√2(9)

x

=

−

4

±

4

2

−

4

(

9

)

(

11

)

2

(

9

)

=−4±16−396‾‾‾‾‾‾‾‾‾√18

x

=

−

4

±

16

−

396

18

=−4±−380‾‾‾‾‾√18

x

=

−

4

±

−

380

18

The discriminant 2−4<0

b

2

−

4

a

c

<

0

so, there are two complex roots.

Simplify the Radical:

=−4±295‾‾‾√18

x

=

−

4

±

2

95

i

18

=−418±295‾‾‾√18

x

=

−

4

18

±

2

95

i

18

Simplify fractions and/or signs:

=−29±95‾‾‾√9

x

=

−

2

9

±

95

i

9

which becomes

=−0.222222+1.08298

x

=

−

0.222222

+

1.08298

i

=−0.222222−1.08298

2. Answer:

=−38±895‾‾‾‾√40

x

=

−

3

8

±

895

i

40

=−0.375+0.747914

x

=

−

0.375

+

0.747914

i

=−0.375−0.747914

x

=

−

0.375

−

0.747914

i

3. Answer:

=0=−74

x

=

0

x

=

−

7

4

=0

x

=

0

=−1.75

Find the Solution for

82+14+0=0

8

x

2

+

14

x

+

0

=

0

using the Quadratic Formula where

a = 8, b = 14, and c = 0

=−±2−4‾‾‾‾‾‾‾‾√2

x

=

−

b

±

b

2

−

4

a

c

2

a

=−14±142−4(8)(0)‾‾‾‾‾‾‾‾‾‾‾‾√2(8)

x

=

−

14

±

14

2

−

4

(

8

)

(

0

)

2

(

8

)

=−14±196−0‾‾‾‾‾‾‾√16

x

=

−

14

±

196

−

0

16

=−14±196‾‾‾‾√16

x

=

−

14

±

196

16

The discriminant 2−4>0

b

2

−

4

a

c

>

0

so, there are two real roots.

Simplify the Radical:

=−14±1416

x

=

−

14

±

14

16

=016=−2816

x

=

0

16

x

=

−

28

16

=0=−74

x

=

0

x

=

−

7

4

which becomes

=0

x

=

0

=−1.75

i hope this helps

8 0
2 years ago
Perform the indicated operation. 4/11 x 10/8
Mrrafil [7]
 5/11 because if you simplify starting at 40/88 you get 5/11
5 0
3 years ago
Read 2 more answers
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