Hello :
<span>(3x²+kx-1) is a quadratic polynome when : a =3 , b=k , c= -1
the discriminat </span>Δ = b²-4ac ≥ 0 because ac = -3 <span><<span> 0
-4ac </span></span>>0 and b²<span>≥0
the </span> quadratic polynome has :2 solutios or 1 solution (Change of sign)
conclusion : <span>is never always positive for any value of k</span>
Sin^2 (2x) = (1 - cos(4x))/2
---> sin^4 (2x) = (1/4)(1 - cos4x)^2 = (1/4)(1 - 2cos4x + cos^2 (4x)) and replace cos^2(4x) by (1/2)(1+cos(8x)) --->answer
to find the angle at point E you would take 180-105. which equals 75.
75+55= 130
180-130=50
Angle D= 50 degrees
Angle C= 55 degrees
Angle E= 75 degrees
Given transformation is f(x+5) which is similar to f(x+h).
f(x+h) shifts the graph "h" units to the left side.
so that means f(x+5) will shift the graph "5" units to the left side.
Left or right movement is done using x-coordinate only so -3 will change in (-3,7)
-3+5=2
so the new coordinate of the point will be (2,7)
Hence final answer is (2,7).
Answer:
知りません
Step-by-step explanation:
