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1 answer:

8 0

(y^2)^5 × y^8
Use the rule:
$({ {y}^{m} })^{n} = {y}^{m \times n}$
To get:
y^10, then, use the rule:
${y}^{m} \times {y}^{n} = {y}^{m + n}$
To eventually get:
y^(10+8) = y^18 or: y18 seeing as you wrote it like that.

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jolli1 [7]

There is 78 square units mark me as brainlist if this helps lol

7 0

2 years ago

Gregorio took two tests. Find his z-score for each test. (Remember: The number of standard deviations between a score and the me

never [62]

I found the missing parts of this question.
Test A
Gregorio’s score 62 
Mean score 80 
Standard deviation 6 

Test B 
Gregorio's score 70 
Mean score 90 
Standard deviation 10 

a. Test A: 3; Test B: 2; Test A 
c. Test A: –2; Test B: –3; Test A 
b. Test A: –3; Test B: –2; Test B 
d. Test A: –3; Test B: –2; Test A


Refer to the attachment for the formula of z score:

test A: z = (62-80)/6 = -18/6 = -3
test B: z = (70-90)/10 = -20/10 = -2

B. Test A: –3; Test B: –2; Test B