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VLD [36.1K]
3 years ago
12

NEEEEEEEEEED ANSWER FFFFFFAAAAAAAAAAASSTTTTTTTT

Mathematics
1 answer:
Firdavs [7]3 years ago
8 0
(y^2)^5 × y^8
Use the rule:
({ {y}^{m} })^{n}  =  {y}^{m \times n}
To get:
y^10, then, use the rule:
{y}^{m}  \times  {y}^{n}  =  {y}^{m + n}
To eventually get:
y^(10+8) = y^18 or: y18 seeing as you wrote it like that.


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