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3 years ago

Work out the area of a triangle of base 7.5 and height 6cm

Mathematics

2 answers:

RideAnS [48]3 years ago

5 0

Area of triangle= 1/2×base×height =1/2×75/10×6 =75/10×3 =225/10 =22.5cm^2

Reptile [31]3 years ago

3 0

The answer should be 22.5

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the number of kilometers a car can drive varies directly with the liters of fuel in the car. this car can travel 476 kilometers

notka56 [123]

For this case we have that the relationship is direct.

Therefore, we have:

$y = k * x$

Where,

y: distance traveled in kilometers

x: number of liters of fuel

k: proportionality constant

We must look for the value of k. For this, we use the following data:

This car can travel 476 kilometers on 17 liters of fuel.

Substituting values we have:

$476 = k * 17$

From here, we clear the value of k:

$k = \frac{476}{17}\\k = 28$

Therefore, the relationship is:

$y = 28x$

For 1428 kilometers we have:

$1428 = 28x$

Clearing the amount of fuel we have:

$x = \frac{1428}{28}\\x = 51$

Answer:

51 liters of fuel are required for the vehicle to travel 1,428 kilometers

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3 years ago

7p – 4p – p <br> need the answer for this

Andrews [41]

$7p - 4p - p \\ \\ 7p - 5p \\ \\ 2p.$

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2 years ago

Evaluate 2y + 4 for y = 15.

postnew [5]

Answer: 34

Step-by-step explanation

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3 years ago

Read 2 more answers

X = ? y = ? 16 45 degrees

mezya [45]

Let's put more details in the figure to better understand the problem:

Let's first recall the three main trigonometric functions:

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $\text{ Tangent }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Adjacent Side}}$

For x, we will be using the Cosine Function:

$\text{ Cosine }\theta\text{ = }\frac{\text{ Adjacent Side}}{\text{ Hypotenuse}}$ $Cosine(45^{\circ})\text{ = }\frac{\text{ x}}{\text{ 1}6}$ $(16)Cosine(45^{\circ})\text{ = x}$ $(16)(\frac{1}{\sqrt[]{2}})\text{ = x}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = x}$

Therefore, x = 8√2.

For y, we will be using the Sine Function.

$\text{ Sine }\theta\text{ = }\frac{\text{ Opposite Side}}{\text{ Hypotenuse}}$ $\text{ Sine }(45^{\circ})\text{ = }\frac{\text{ y}}{\text{ 1}6}$ $\text{ (16)Sine }(45^{\circ})\text{ = y}$ $\text{ (16)(}\frac{1}{\sqrt[]{2}})\text{ = y}$ $\text{ }\frac{16}{\sqrt[]{2}}\text{ x }\frac{\sqrt[]{2}}{\sqrt[]{2}}\text{ = }\frac{16\sqrt[]{2}}{2}$ $\text{ 8}\sqrt[]{2}\text{ = y}$

Therefore, y = 8√2.

5 0

1 year ago

I want to know the answer of A to self check the answer i got! Would you write the expression and take away the area of the inte

V125BC [204]

It is said the blue card is a rectangle, so you don’t have to minus the inside rectangle. :)

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3 years ago