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3 years ago

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Mathematics

2 answers:

masya89 [10]3 years ago

8 0

Answer:

Part A = the middle one

Part B = 4 days

Step-by-step explanation:

1,300 / 4 = 325

325 x 4 = 1,300

igor_vitrenko [27]3 years ago

7 0

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in a state with a population of 2000000 the average vitizen spends 6000 on housing each year. what is the total spent on housing

Olenka [21]

Answer:

$1.2 \times 10^{10}$ spents on housing for each year for the state.

Step-by-step explanation:

Given:

Population of State = 2000000

Average Citizen spends on housing = 6000

We need to find total spent on housing for the state.

For finding total spent on housing for state we need to multiply Population of state with average citizen spends on housing.

Total spent on housing for state = Population of State $\times$ Average Citizen spends on housing = $2000000 \times 6000 = 12000000000$

Now expressing the above in scientific notation we get;

Total spent on housing for state = $1.2 \times 10 ^{10}$

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2 years ago

Help me me please https://brainly.com/question/22734415

matrenka [14]

Answer:

2) 1

3) 9

4) 78

Step-by-step explanation:

1 showed up the most

range = max value - min value

range = 9 - 0

range = 9

mode means which showed up the most,

78 showed up the most

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2 years ago

Solve this problem 3L /2 = 2/3 what is the value of L

NISA [10]

Answer:

4/9

Step-by-step explanation:

3L /2 = 2/3 cross multiply expressions

9L = 4 divide both sides by 9

L = 4/9

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2 years ago

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The quotient of two negative integers results in an integer how does the value of the quotient compared to the value of the orig

Annette [7]

The value of the quotient will result in a positive integer compared to the original two integers that started off as a negative integer

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3 years ago

Power +, Inc. produces AA batteries used in remote-controlled toy cars. The mean life of these batteries follows the normal prob

Novay_Z [31]

Answer:

a) By the Central Limit Theorem, it is approximately normal.

b) The standard error of the distribution of the sample mean is 1.8333.

c) 0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d) 0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours

e) 0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 36 hours and a standard deviation of 5.5 hours.

This means that $\mu = 36, \sigma = 5.5$

a. What can you say about the shape of the distribution of the sample mean?

By the Central Limit Theorem, it is approximately normal.

b. What is the standard error of the distribution of the sample mean? (Round your answer to 4 decimal places.)

Sample of 9 means that $n = 9$ . So

$s = \frac{\sigma}{\sqrt{n}} = \frac{5.5}{\sqrt{9}} = 1.8333$

The standard error of the distribution of the sample mean is 1.8333.

c. What proportion of the samples will have a mean useful life of more than 38 hours?

This is 1 subtracted by the pvalue of Z when X = 38. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{38 - 36}{1.8333}$

$Z = 1.09$

$Z = 1.09$ has a pvalue of 0.8621

1 - 0.8621 = 0.1379

0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d. What proportion of the sample will have a mean useful life greater than 34.5 hours?

This is 1 subtracted by the pvalue of Z when X = 34.5. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{34.5 - 36}{1.8333}$

$Z = -0.82$

$Z = -0.82$ has a pvalue of 0.2061.

1 - 0.2061 = 0.7939

0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours.

e. What proportion of the sample will have a mean useful life between 34.5 and 38 hours?

pvalue of Z when X = 38 subtracted by the pvalue of Z when X = 34.5. So

0.8621 - 0.2061 = 0.656

0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

4 0

2 years ago