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Mashutka [201]
3 years ago
15

What is 5.8 x 10^6 seconds in minutes?

Mathematics
1 answer:
IrinaK [193]3 years ago
8 0

Answer: here you go (PIC)

<h2>ITS B</h2>

hope it helps




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Help me, I will give the brainlyest to the smartest and the fastest!
lora16 [44]

Answer:

{(1,4) (2,8) (3,12) (4,16)}

4 0
3 years ago
Where does the graph of the line y = x - 2 intersect the x-axis?
Shkiper50 [21]

Answer:

Where does the graph of the line y = x - 2 intersect the x-axis?

O A. (0, 2)

O B. (2,0)

O C. (0, -2)

0 D. (-2, 0)

C. ( 0 , -2 )

Step-by-step explanation:

I hope this helps

Follow // Followback

3 0
3 years ago
Drag the expressions into the boxes to correctly complete the table.
lora16 [44]

Answer:

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

3 0
3 years ago
Find an equation of the line parallel to y=2x+3 and that passes through the point (5,3)
timama [110]

Answer:

y = 2x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 2x + 3 ← is in slope- intercept form

with slope m = 2

Parallel lines have equal slopes , then

y = 2x + c ← is the partial equation

To find c substitute (5, 3 ) into the partial equation

3 = 10 + c ⇒ c = 3 - 10 = - 7

y = 2x - 7 ← equation of parallel line

5 0
2 years ago
Read 2 more answers
Why will the value of y for the function y equals 5x + 1 always be greater than that of y equals 4x + 1 with X greater than 1?
klemol [59]
You mean
the linear equations, 5x-y+1=0,4x-y+1=0
the slopes are 5 and 4 respectively.
it is clear that slope of first equation is greater that is it has a steeper graph therefore it Will always be greater than the other for x > 1
the same can be done by calculus; differentiation.

note y=5x+1 is always greater than y=4x+1 for all x>1
4 0
3 years ago
Read 2 more answers
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