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mezya [45]
3 years ago
13

Consider the figure shown below. How long is XZ?

Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0
It has to be 5
.......
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Distance between (-5, -5) And (-9, -2)
Sergeeva-Olga [200]
d =  \sqrt{(x_2 - x_1)^2+(y_2-y_1)^2}  \\ d =  \sqrt{(-9 - (-5))^2+(-2 - (-5))^2}  \\ d =  \sqrt{(-4)^2+(3)^2}  \\ d =  \sqrt{16 + 9}  \\ d =  \sqrt{25} = 5
5 0
2 years ago
How do I factor trinomials of a form ax^2+bx+c when a=1 <br><br> In one paragraph
vitfil [10]

Answer:

  • Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

Step-by-step explanation:

As we know that a polynomial with three terms is said to be a trinomial.

Considering the trinomial of a form

ax^2+bx+c

As

a = 1

so

x^2+bx+c

  • Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

For example,

x^2+7x+10

=\left(x^2+2x\right)+\left(5x+10\right)

=x\left(x+2\right)+5\left(x+2\right)

\mathrm{Factor\:out\:common\:term\:}x+2

=\left(x+2\right)\left(x+5\right)

Therefore, Trinomials in the form x^2+bx+c can often be factored as the product of two binomials.

6 0
2 years ago
Solve this: k/3 = -4​
Veseljchak [2.6K]

Step-by-step explanation:

  • k/3= -4
  • k= -4×3
  • k= -12

<h2>stay safe healthy and happy.</h2>
6 0
2 years ago
Read 2 more answers
On a coordinate plane, a circle has a center at (0, 0). Point (3, 0) lies on the circle.
9966 [12]

Answer:

The correct option is;

No, the distance from (0, 0) to (2, √6) is not 3 units

Step-by-step explanation:

The given parameters of the question are as follows;

Circle center (h, k) = (0, 0)

Point on the circle (x, y) = (3, 0)

We are required to verify whether point (2, √6) lie on the circle

We note that the radius of the circle is given by the equation of the circle as follows;

Distance \, formula = \sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}}

Distance² = (x - h)² + (y - k)² = r² which gives;

(3 - 0)² + (0 - 0)² = 3²

Hence r² = 3² and r = 3 units

We check the distance of the point (2, √6) from the center of the circle (0, 0) as follows;

\sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}} = Distance

Therefore;

(2 - 0)² + (√6 - 0)² = 2² + √6² = 4 + 6 = 10 = √10²

\sqrt{\left (2-0 \right )^{2} + \left (\sqrt{6} -0 \right )^{2}} = 10

Which gives the distance of the point (2, √6) from the center of the circle (0, 0) = √10

Hence the distance from the circle center (0, 0) to (2, √6) is not √10 which s more than 3 units hence the point  (2, √6), does not lie on the circle.

4 0
3 years ago
Read 2 more answers
Substitute each given value of the variable to find which, if any, is a solution of inequality.
OlgaM077 [116]

Given:

The inequalities are:

a) w

b) t>-25, t=-24, -25, -25.1, -27

To find:

The solution of inequalities by substituting the given values.

Solution:

a) We have,

w

After substituting the given values one by one, we get

-4.3 False statement.

-5.3 False statement.

-8.3 True statement.

-9 True statement.

Therefore the solutions of w are w=-8.3, -9.

b)

We have,

t>-25, t=-24, -25, -25.1, -27

After substituting the given values one by one, we get

-24>-25 True statement.

-25>-25 False statement.

-25.1>-25 False statement.

-27>-25 False statement.

Therefore, the solution of t>-25 is t=-24.

8 0
3 years ago
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