Alright finding the mean of the set is pretty simple,
first add all the numbers that you were given.
0+2+3+4+6+6+7 add these up
28 then you need to divide them by
you divide by 7 because that's how many numbers you have
28 divided by 7 equals 4
so Sandy is correct.
72 + 12x = 24 + 24x
48 = 12x
4 = x
It‘ll take 4 years.
From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:
[$19.5, $22.5].
<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>
The confidence interval is given by the sample mean plus/minus the margin of error, hence:
- The lower bound is the sample mean subtracted by the margin of error.
- The upper bound is the sample mean added to the margin of error.
For this problem, we have that:
- The sample mean is of $21.
- The margin of error is of $1.50.
Hence the bounds are given as follows:
- Lower bound: 21 - 1.50 = $19.50.
- Upper bound: 21 + 1.50 = $22.50.
Hence the interval is [$19.50, $22.50].
More can be learned about confidence intervals at brainly.com/question/25890103
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Sample space ={1,2,3,4,5,6,} =6 possible outcome
P(getting 5) = 1/6
P(NOT getting 5) = 1-1/6 = 5/6 = 0.834
Or NOT getting 5 means GETTING 1,2,3,4,6 = 5 favorable outcome &
P(NOT getting 5) = / =
