What is the equation in point slope form of the line that passes through the point
1 answer:
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Answer:
72.3
Step-by-step explanation:
Given that:
The arithmetic sequence:
The first term of the sequence = 3 since k = 0
i.e (3 + 0.26(0)) = 3
The last term of the sequence = 6.64
i.e (3+ 0.26(14)
= (3 + 3.64)
= 6.64
Total no of terms = 15 i.e from 0 to 14
∴
The partial sum of the arithmetic sequence =
= 72.3
Answer:
-3 1/3
Step-by-step explanation:
The quadratic
... y = ax² +bx +c
has its extreme value at
... x = -b/(2a)
Since a = 3 is positive, we know the parabola opens upward and the extreme value is a minimum. (We also know that from the problem statement asking us to find the minimum value.) The value of x at the minimum is -(-4)/(2·3) = 2/3.
To find the minimum value, we need to evaluate the function for x=2/3.
The most straightforward way to do this is to substitue 2/3 for x.
... y = 3(2/3)² -4(2/3) -2 = 3(4/9) -8/3 -2
... y = (4 -8 -6)/3 = -10/3
... y = -3 1/3
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<em>Confirmation</em>
You can also use a graphing calculator to show you the minimum.
