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3 years ago

Sorry bout that, THIS IS THE NEW ONE PLEASE ANSWER

Mathematics

1 answer:

Sergio039 [100]3 years ago

3 0

Answer:

Step-by-step explanation:

Putting value of y = 5

4(5)2 - 7(5) - 6

4(25) - 35 - 6

100 - 41

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Which simplified ratio correctly compares 5 meters to 100 centimeters

Greeley [361]

5:1 since 100 cm is = to 1 meter

5 0

3 years ago

. sipho buys a car for r169 000. he pays a deposit of 15% and then makes monthly installments of 1% of the leftover amount for 9

Aliun [14]

The amount for the deposit is $25350, monthly payment is $1436.5 and the total amount that Sipho pays is $178492.

Given price of car $169000, deposit of 15%, monthly installments being 1% of left over price and number of years be 9 years.

We have to find the amount of deposit, monthly installments and the total amount paid by Sipho.

We have been told that deposit is 15% of total amount. So the deposit will be 15%*169000=$25350.

Monthly installment is 1% of the left over amount.

left amount=169000-25350=$143650.

Monthly installment being =143650*1/100

=$1436.5

Total amount paid by Sipho=deposit +installment amount * numberof installments

Number of installments=12*9

=108

Total amount=25350+1436.5*108

=25350+155142

=$178492

Hence deposit is $25350, monthly payment being $1436.5, total amount be $178492.

Learn more about installments at brainly.com/question/2151013

#SPJ4

5 0

1 year ago

Vladimir has 64 coins of .25 cents and 56 coins for .50 cents. What is the greatest number of identical packs of coins with no c

Zina [86]

Answer:

56 coins for 0.50 cents

Step-by-step explanation:

3 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

30 POINTS + BRAINLIEST TO FIRST CORRECT ANSWER!

Vinvika [58]

Answer:

The length will be multiplied by 2.

Step-by-step explanation:

By looking at the first and third ratio, we know that the no. of birck have been multiplied by 2 and the length has also been multiplied by 2 .

So when the number of bricks is multiplied by 2, the length is multiplied by 2

7 0

3 years ago

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