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3 years ago

How to simplify mixed numberl

1 answer:

4 0

You multiply the whole number and multiply the denominator (the bottom one of the fraction) then you take the product and add the numerator (the top one of the fraction). That's how you get an improper fraction. Then once you get and improper fraction, you divide the numerator and denominator by their common factors. That's how you simply a mixer number.

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What best describes the end behavior of the graph of f(x)=-x^4+5x-5

Neko [114]

Answer:

It describes multiplication

Step-by-step explanation:

As you can see its 5x-5 (the x is say "by" or "of), So when you look at it you can clearly see it's multiplication.

8 0

3 years ago

This table models continuous function f.

Tanya [424]

The answer to this is C

3 0

1 year ago

1 For each line

Elena-2011 [213]

Step-by-step explanation:

I'll do line A for you and you can use the formulas to solve lines B and C yourself, since its good for you to practice doing these questions yourself

The gradient, m, is calculated using m = (y2-y1)/(x2-x1) where x1,x2,y1 and y2 can be any ordered pairs on the line. I'm going to use (4,0) and (7,3) as the 2 points.

m = (3-0)/(7-4) = 3/3 = 1

The y-intercept is where the line intersects with the x-axis. In this case (0,-4)

The equation of a linear line is y=mx+b (or c depending on which country you are from)

y = 1x-4

y=x-4

Now try the other 2 lines yourself!

If this answer has helped you, considered making this the brainliest answer!

5 0

2 years ago

Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer

almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

$\to \mu=\frac{\sum xi}{n}$

$=22.8$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187$

In point b:

$\to \mu=\frac{\sum xi}{n}$

$=20.6875$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251$

In point c:

$\to \mu=\frac{\sum xi}{n}$

$=21$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179$

In point d:

$\to \mu=\frac{\sum xi}{n}$

$=20.8375$

$\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}$

$=\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\ =\sqrt{0.553166667} \\\\ =0.7438$

6 0

3 years ago

At 12 noon a ship going due east at 12 knots crosses 10 nautical miles ahead of a second ship going due north at 16 knots

mixas84 [53]

6t-10is the awsner. If s is the number of nautical miles separating the ships, express s in terms of t(the number of hours after 12 noon). I formed the equation s squared to the second power equals (12t) squard to the second power + (10 - 16) squared to the second power

7 0

3 years ago