Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
The answer would be 10/12
The best and most correct answer among the choices provided by your question is the second choice or letter B.
<span> CM is perpendicular to AB because the triangles are isosceles and scalene.
</span>I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
The measure of a supplement of an angel is 6 times the measurement of the complement angle.
(3, –2) and (6, 2)First, we must establish slope...m=(y-y1)/(x-x1)m=(-2-2)/(3-6)m=-4/-3m=4/3Point slope formula is...y-y1=m(x-x1)Let's select either coordinate. I randomly select the first (3, –2)...y--2=4/3(x-3)Subtracting a negative number is the same as adding a positive number...y+2=4/3(x-3)This corresponds to the first answer.Standard form...Ax+By=Cy+2=(4/3)x-4y=(4/3)x-6-(4/3)x+y=-6Multiply both sides by 3...-4x+3y=-18This also corresponds to the first answer. How about the second coordinate, (6, 2)...y-y1=m(x-x1)y-2=(4/3)(x-6)Let's convert it into standard form..y-2=(4/3)x-8y=(4/3)x-6-(4/3)x+y=-6Multiply both sides by 3...-4x+3y=-18
