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Inessa05 [86]
3 years ago
15

A construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. If the buildi

ng is expected to be 200 feet tall, how tall will the model be
Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0

Let x represent the height of the model.

We have been given that a construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. We are asked to find the height of the model, if  the building is expected to be 200 feet tall.

We will use proportions to solve our given problem as:

\frac{\text{Model height}}{\text{Actual height}}=\frac{\text{Model length}}{\text{Actual length}}

Upon substituting our given values, we will get:

\frac{x}{200\text{ ft}}=\frac{3\text{ in}}{\text{32 ft}}

\frac{x}{200\text{ ft}}\times 200\text{ ft}=\frac{3\text{ in}}{\text{32 ft}}\times 200\text{ ft}

x=3\text{ in}\times 6.25

x=18.75\text{ in}

Therefore, the model will be 18.75 inches tall.

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What is the approximate value for the modal daily sales?
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Answer:

Step-by-step explanation:

Hello!

<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected  days </em>

<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>

<em>Days 18 27 31 40 56 55 23 </em>

<em>Use it to answer questions 13 and 14. </em>

<em>13. What is the approximate value for the modal daily sales? </em>

To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)

The modal interval is [3.1-3.5]

Now using the following formula you can calculate the Mode:

Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ]

Li= Lower limit of the modal interval.

c= amplitude of modal interval.

fmax: absolute frequency of modal interval.

fprev: absolute frequency of the previous interval to the modal interval.

fpost: absolute frequency of the posterior interval to the modal interval.

Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47

<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>

Of all options the closest one to the estimated mode is A.

<em>14. The approximate median daily sales is … </em>

To calculate the median you have to identify its position first:

For even samples: PosMe= n/2= 250/2= 125

Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.

F(1)= 18

F(2)= 18+27= 45

F(3)= 45 + 31= 76

F(4)= 76 + 40= 116

F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]

Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ]

Li: Lower limit of the median interval.

c: Amplitude of the interval

PosMe: position of the median

F(i-1)= accumulated absolute frequency until the previous interval

fi= simple absolute frequency of the median interval.

Me= 3,100+400[\frac{125-116}{56} ]= 3164.29

<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>

Of all options the closest one to the estimated mode is C.

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3 years ago
3/4 a - q = k, solve for a
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Answer: a = 4k + 4q ÷ 3

Step-by-step explanation:

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Jeff wants to know how many miles it is from his house to school. On a map the distance is 3 inches. If the scale is 1/2 inch fo
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Answer:

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Step-by-step explanation:

1/2 inch per 2 miles

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Suppose you want to accumulate $25,000 as down payment on a house and the best you can do is to put aside $200 a month. If you d
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Answer:

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The number of monthly installments required to amount to FV is given by;

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Which measurement is equal to 6 kilograms?
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